Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 3)
3.
Determine the angle
: = 30° = 40° = 60° = 50°Discussion:
30 comments Page 2 of 3.
Er. jagdeep yadav said:
1 decade ago
In 2nd fig.
One angle is 90degree.
One angle is alternate which is 40 degree.
So total is 180 on a line then.
90+40+x=180.
X=180-130.
X=50.
One angle is 90degree.
One angle is alternate which is 40 degree.
So total is 180 on a line then.
90+40+x=180.
X=180-130.
X=50.
Rajasekhar said:
1 decade ago
Sum of triangle = 180 from fig 1 the angle specified next to theta is 40 opposite exterior angles are equal which is 40
x+90+40=180
x=180-130=50
x+90+40=180
x=180-130=50
Prasad said:
1 decade ago
The first figure, I guess is wrong. The other angle other than 40 degree and theta is supposed to be perpendicular. It is moreover confusing.
Rajanishree ks said:
1 decade ago
Kindly mention the details of the error here...
see nohin error here act its right ans. watch fig 3, 90'=50'+40' thats it..:)
see nohin error here act its right ans. watch fig 3, 90'=50'+40' thats it..:)
KIRAN said:
1 decade ago
IN FIG 1
40+90+ THE ANGLE
THAT IS 40+90+ANGLE =180
THERE FOR ANGLE = 50 THAT'S IT........ SIMPLE
40+90+ THE ANGLE
THAT IS 40+90+ANGLE =180
THERE FOR ANGLE = 50 THAT'S IT........ SIMPLE
Darpan said:
1 decade ago
In geometry there is one rule in that case the angle given other than thita is equal to 40. So for theta 90-40=50.
Edy said:
1 decade ago
Total Angle 1 Triangle = 180.
Know One Angle 40.
So 40 + 90 + X = 180.
X = 180 - 90 + 40.
X = 180 - 130.
X = 50.
Know One Angle 40.
So 40 + 90 + X = 180.
X = 180 - 90 + 40.
X = 180 - 130.
X = 50.
Anish kur said:
1 decade ago
In fig 2 ,considering the alternate angles we get
40+x+90=180
x=50,where x=theta(required angle)
40+x+90=180
x=50,where x=theta(required angle)
Neeraja said:
1 decade ago
In the second fig since alternate angles are equal
40=90-theta
then theta=90-40
=50
40=90-theta
then theta=90-40
=50
Akanksha said:
1 decade ago
In fig 1
40+90+x=180
x=50
In fig 2 , alternate angles we get
40+x+90=180
x=50,
40+90+x=180
x=50
In fig 2 , alternate angles we get
40+x+90=180
x=50,
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