Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 3)
3.
Determine the angle
: = 30° = 40° = 60° = 50°Discussion:
30 comments Page 2 of 3.
Manish yadav said:
1 decade ago
In first figure, angle b/w two line is 90 then
40+90+x=180.
X=50.
40+90+x=180.
X=50.
Udayan singh said:
1 decade ago
In fig1- if unmentiond angle is90 then theta =5:
fig2: theta+90+40=ans.
Fig3: the angle besides the 40 must b a rit angle then theta =501
net ans for theta in thrice case to b 50.
fig2: theta+90+40=ans.
Fig3: the angle besides the 40 must b a rit angle then theta =501
net ans for theta in thrice case to b 50.
Darpan said:
1 decade ago
In geometry there is one rule in that case the angle given other than thita is equal to 40. So for theta 90-40=50.
Akanksha said:
1 decade ago
In fig 1
40+90+x=180
x=50
In fig 2 , alternate angles we get
40+x+90=180
x=50,
40+90+x=180
x=50
In fig 2 , alternate angles we get
40+x+90=180
x=50,
Rajanishree ks said:
1 decade ago
Kindly mention the details of the error here...
see nohin error here act its right ans. watch fig 3, 90'=50'+40' thats it..:)
see nohin error here act its right ans. watch fig 3, 90'=50'+40' thats it..:)
Anish kur said:
1 decade ago
In fig 2 ,considering the alternate angles we get
40+x+90=180
x=50,where x=theta(required angle)
40+x+90=180
x=50,where x=theta(required angle)
Sathish kumar said:
1 decade ago
From the fig
(90-x)+40=180
x=180-(90+40)
Hence x=50
(90-x)+40=180
x=180-(90+40)
Hence x=50
Damodaran said:
1 decade ago
Still I'm not clear could you explain me in more in detail.
Brahmananda Reddy said:
1 decade ago
In third fig we have an ang bisector. So we get 40 again. Ang bisector divides 80 into 40 each. So from alternate angles principle we will get ans as 40.
THIRUPATHAIAH said:
1 decade ago
40 degrees is given vertically according to alternative angle beside the theta angle is 40 degrees we know that t+40=90 then t=50 degrees where t is theta
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