Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 9)
9.
Solve the following equation for the two roots of x: — x2 + 5x = — 6
Discussion:
13 comments Page 2 of 2.
Don said:
1 decade ago
We can write the equation:
x^2-5x+6 = 0.
x^2-2x-3x+6 = 0.
x(x-2)-3(x-2) = 0.
(x-2)(x-3) = 0.
=>(x-2) or (x-3) = 0.
> x = 2 or 3.
x^2-5x+6 = 0.
x^2-2x-3x+6 = 0.
x(x-2)-3(x-2) = 0.
(x-2)(x-3) = 0.
=>(x-2) or (x-3) = 0.
> x = 2 or 3.
NAYAN said:
1 decade ago
x^2-5x-6 = 0.
x^2-(3+2)x-6 = 0.
x^2-3x+2x-6 = 0.
x(x-2)+2(x-3) = 0.
(x-3)(x+2) = 0.
x = -2, 3.
x^2-(3+2)x-6 = 0.
x^2-3x+2x-6 = 0.
x(x-2)+2(x-3) = 0.
(x-3)(x+2) = 0.
x = -2, 3.
Gayathri said:
10 years ago
x2-5x = 6.
x2-5x-6 = 0.
x2-6x+x-6 = 0.
x(x-6)+1(x-6) = 0.
(x-6) = 0,(x+1) = 0.
x = 6,-1.
x2-5x-6 = 0.
x2-6x+x-6 = 0.
x(x-6)+1(x-6) = 0.
(x-6) = 0,(x+1) = 0.
x = 6,-1.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers