Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 6)
6.
Determine the angles
and 
and the length of side AB of the triangle. Note that there are two possible answers to this question and we have provided only one of them as an answer. = 46.7°, = 93.3° d = 9.22 = 50.0°, = 90.0° d = 9.14 = 40.0°, = 100.0° d = 9.22 = 48.6°, = 91.4°, d = 9.33Discussion:
17 comments Page 2 of 2.
Shubham said:
9 years ago
Guys here we can't use trigonometry relations.
Because one of them angle is not 90°.
Because one of them angle is not 90°.
Ammu said:
1 decade ago
Why cant we use cos40=7/AB=>AB=9.14 directly......it is also correct method.
Hasi said:
1 decade ago
It would be better to give a small description for angles also...
Nitish said:
1 decade ago
Using sine formula,
a/sin A = b/sin B
6/sin 40 = 7/sin CBA
a/sin A = b/sin B
6/sin 40 = 7/sin CBA
Preethi said:
2 decades ago
sin 40'= 6/ab
AB= 6/SIN 40
AB= 9.33
option d
AB= 6/SIN 40
AB= 9.33
option d
Damodaran said:
1 decade ago
I'm confused please let me clear.
PRAMOD said:
1 decade ago
COS40=7/AB
AB=7/COS40
AB=9.13
AB=7/COS40
AB=9.13
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