Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 6)
6.
Determine the angles
and 
and the length of side AB of the triangle. Note that there are two possible answers to this question and we have provided only one of them as an answer. = 46.7°, = 93.3° d = 9.22 = 50.0°, = 90.0° d = 9.14 = 40.0°, = 100.0° d = 9.22 = 48.6°, = 91.4°, d = 9.33Discussion:
17 comments Page 2 of 2.
Kcrkr said:
1 decade ago
Please let me know why you are using Sin theta, I think sin is using against for length / hypotenus, we get for cos theta also because we know base of triangle. Then answer is 9.22.
Aviral Singh said:
1 decade ago
In triangle ABC, taking AC as the base of the triangle
i.e. 7 units
and height BC i.e. 6 units
Then, Sin40=6/AB
Hence, AB=6/Sin40
Therefore, AB=9.33
Now using sine formula 7/sinCBA=6/sin40
Therefore SinCBA=0.7499
so Angle CBA=48.58
Now AngleACB,, ACB+40+48.58=180
Angle ACB=91.42
ANSWER: Option D
i.e. 7 units
and height BC i.e. 6 units
Then, Sin40=6/AB
Hence, AB=6/Sin40
Therefore, AB=9.33
Now using sine formula 7/sinCBA=6/sin40
Therefore SinCBA=0.7499
so Angle CBA=48.58
Now AngleACB,, ACB+40+48.58=180
Angle ACB=91.42
ANSWER: Option D
Damodaran said:
1 decade ago
I'm confused please let me clear.
Nitish said:
1 decade ago
Using sine formula,
a/sin A = b/sin B
6/sin 40 = 7/sin CBA
a/sin A = b/sin B
6/sin 40 = 7/sin CBA
Kumar said:
1 decade ago
Hai Preethi you said answer for this problem is only applicable for right angled triangle, but it is not a right angled triangle.
Hasi said:
1 decade ago
It would be better to give a small description for angles also...
Hemu Singh said:
1 decade ago
If the sides of the triangle are a=6, b=7,and AB=d (let)
then according to cosine triangle formula
COS(A)= (b^2 + c^2 - a^2)/2bc
Where A=40'
d = 9.33 & 1.39
So ans. is option d....
then according to cosine triangle formula
COS(A)= (b^2 + c^2 - a^2)/2bc
Where A=40'
d = 9.33 & 1.39
So ans. is option d....
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