Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 4)
4.
Solve the following equation for x, y, and z:
x – y + z = –1 –x + y + z = –1 x + 2y – 2z = 5
Discussion:
14 comments Page 2 of 2.
Samarth Patel said:
1 decade ago
First 2 equ
x-y+z=-1
-x+y+z=-1 solve this equ we get the value of z=-1,
now wesolve the last 2 equ and we get the value of y=1,
and last we can add the value of y & z in any equ, we can get the x=1 so that we can solve this
x=1,y=1,z=-1
x-y+z=-1
-x+y+z=-1 solve this equ we get the value of z=-1,
now wesolve the last 2 equ and we get the value of y=1,
and last we can add the value of y & z in any equ, we can get the x=1 so that we can solve this
x=1,y=1,z=-1
Manpreet said:
1 decade ago
First you should put x & y =0
then 0 + z = -1
z = -1
put this in 1 equation
it wil x - y = 0
x = y
put this in 3 equation
x + 2x - 2(-1) = 5
3x + 2 = 5
3x = 3
x = 1 so answer is x = 1 y = 1 z = -1
then 0 + z = -1
z = -1
put this in 1 equation
it wil x - y = 0
x = y
put this in 3 equation
x + 2x - 2(-1) = 5
3x + 2 = 5
3x = 3
x = 1 so answer is x = 1 y = 1 z = -1
Arpita majumder said:
1 decade ago
x-y+z=-1
=>x-y-1+x-y=-1(putting value of z fm 2nd eqn0
=>2(x-y)=0
=>x=y
putting x=y in 1st eqn
=>z=-1
putting x=y in 3rd eqn
=>3x-2z=5
=>x=1(z=-1)
as x=1,y=1
hence,x=1,y=1 & z=-1
=>x-y-1+x-y=-1(putting value of z fm 2nd eqn0
=>2(x-y)=0
=>x=y
putting x=y in 1st eqn
=>z=-1
putting x=y in 3rd eqn
=>3x-2z=5
=>x=1(z=-1)
as x=1,y=1
hence,x=1,y=1 & z=-1
Karthik said:
1 decade ago
Substitute each value un the equation whichever satisfies the equation is the answer.
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