Engineering Mechanics - Friction - Discussion
Discussion Forum : Friction - General Questions (Q.No. 4)
4.
The refrigerator has a weight of 200 lb and a center of gravity at G. Determine the force P required to move it. Will the refrigerator tip or slip? Take 
= 0.4.
Discussion:
11 comments Page 2 of 2.
JAYA DEVA CHARYA said:
3 years ago
In this case, the maximum static friction value is = 0.4*200 = 80lb (Force required to move the body in a linear direction or slide the body)
Taking moment about at the tipping position,
P*4 = 1.5*200
P = 75lb ( Tipping condition).
So, since the value of tipping is less it will occur first the body will tip first with 75lb of force.
Taking moment about at the tipping position,
P*4 = 1.5*200
P = 75lb ( Tipping condition).
So, since the value of tipping is less it will occur first the body will tip first with 75lb of force.
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