Engineering Mechanics - Force Vectors - Discussion
Discussion Forum : Force Vectors - General Questions (Q.No. 9)
9.
The cable AO exerts a force on the top of the pole of F = {—120i — 90j — 80k} lb. If the cable has a length of 34 ft, determine the height z of the pole and the location (x,y) of its base.
Discussion:
3 comments Page 1 of 1.
Grant said:
7 years ago
√ 120^2+90^2+80^2 = is the magnitude of the resultant force.
Charles said:
7 years ago
How did you got the resultant force be 170?
Sudipta jana said:
1 decade ago
Here the force f has its value along x, y, z directions are 120, 90, 80.
So the resultant force is equal to 170.
So the angles are along x, y, z cos inverse of
(9120/170),(90/170),(80/170).
Now the length of the cable is 34.
So the components along,
x axis 34*(120/170) = 24.
y axis 34*(90/170) = 18.
z axis 34*(80/170) = 16.
So the resultant force is equal to 170.
So the angles are along x, y, z cos inverse of
(9120/170),(90/170),(80/170).
Now the length of the cable is 34.
So the components along,
x axis 34*(120/170) = 24.
y axis 34*(90/170) = 18.
z axis 34*(80/170) = 16.
(1)
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