Engineering Mechanics - Force Vectors - Discussion
Discussion Forum : Force Vectors - General Questions (Q.No. 8)
8.
The antenna tower is supported by three cables. The forces in these cables are as follows: FB = 520 N, FC = 680 N, and FD = 560 N. Write the resultant of these three forces as a vector.
Discussion:
7 comments Page 1 of 1.
Happison Nyenyewa said:
3 years ago
The height is 24.
B = (0,-10,24) C=(16,18,-24) D=(-12,8,-24).
|FB| = 26, |FC|=34, |FD|=28.
FB = 520(-10i-24j/|FB|)= 0i-200j-480k.
FC = 680(16i+18j+-24k/|FC|)= 320i + 360j - 480k.
FD = 560(-12i+8j-24k/|FD|)=-240i + 160j - 480k.
F= (80i+320j-1440k)N.
B = (0,-10,24) C=(16,18,-24) D=(-12,8,-24).
|FB| = 26, |FC|=34, |FD|=28.
FB = 520(-10i-24j/|FB|)= 0i-200j-480k.
FC = 680(16i+18j+-24k/|FC|)= 320i + 360j - 480k.
FD = 560(-12i+8j-24k/|FD|)=-240i + 160j - 480k.
F= (80i+320j-1440k)N.
Christbearer said:
8 years ago
According to me, the height of the tower is 24.
Sarvesh said:
8 years ago
Here height of the pole is needed.
Eelove said:
8 years ago
Please explain the solution to this problem.
Thato said:
8 years ago
How to solve this question?
Explain it.
Explain it.
Rohail said:
10 years ago
Can anyone tell me how to solve this problem?
Sunil said:
1 decade ago
Without giving height,is it possible to solve??I need steps to solve this problem.
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