Engineering Mechanics - Force Vectors - Discussion
Discussion Forum : Force Vectors - General Questions (Q.No. 10)
10.
The ball joint is subjected to the three forces shown. Find the magnitude of the resultant force.
Discussion:
2 comments Page 1 of 1.
Jaya Deva Charya said:
3 years ago
The summation along x direction - 1.25 kn
The summation along y direction - F3cosθ - F2sin30 = 2 * (4/5) - 5 * 1/2 = -0.9.
The summation along z direction - F3sinθ + F2cos30 = 2 * (3/5) + 5 * √(3)/2 = 5.53.
Resultant Force = sqrt( 1.25^2 + (-0.9)^2 + 5.53^2) = √(32.9534) = 5.74 KN.
The answer should be B.
The summation along y direction - F3cosθ - F2sin30 = 2 * (4/5) - 5 * 1/2 = -0.9.
The summation along z direction - F3sinθ + F2cos30 = 2 * (3/5) + 5 * √(3)/2 = 5.53.
Resultant Force = sqrt( 1.25^2 + (-0.9)^2 + 5.53^2) = √(32.9534) = 5.74 KN.
The answer should be B.
(1)
Cj manglalan said:
1 decade ago
for
F1X = 1.25 (since f1 is parallel to x- axis)
F2y = 5(sin 30) = 2.5
F2z = 5(cos 30) = 4.330
F3y = 2(3/5) = 1.2
F3z = 2(4/5) = 1.6
summation along x = 1.25 = 1.25
summation along y = -2.5 + 1.2 = -1.3
summatiob along z = 4.330+1.6 = 5.93
R = SQUARE ROOT OF (fx+fy+fz)
R = SQUARE ROOT OF ((1.25)square)+ ((-1.3)square + ((5.93)square)
R = 6.20 KN
F1X = 1.25 (since f1 is parallel to x- axis)
F2y = 5(sin 30) = 2.5
F2z = 5(cos 30) = 4.330
F3y = 2(3/5) = 1.2
F3z = 2(4/5) = 1.6
summation along x = 1.25 = 1.25
summation along y = -2.5 + 1.2 = -1.3
summatiob along z = 4.330+1.6 = 5.93
R = SQUARE ROOT OF (fx+fy+fz)
R = SQUARE ROOT OF ((1.25)square)+ ((-1.3)square + ((5.93)square)
R = 6.20 KN
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