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Engineering Mechanics - Force Vectors - Discussion

Discussion Forum : Force Vectors - General Questions (Q.No. 26)
Force Vectors
26.

Express each force in Cartesian vector form.

F1 = (2.50 i + 3.54 j + 2.50 k) kN, F2 = -2 j kN
F1 = (4.33 i + 3.54 j + 4.33 k) kN, F2 = -2 j kN
F1 = (2.17 i + 3.75 j + 4.33 k) kN, F2 = -2 j kN
F1 = (4.33 i + 3.75 j + 2.17 k) kN, F2 = -2 j kN
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
1 comments Page 1 of 1.
Venkat said:   1 decade ago
F_1_x = 5kN cos60 = 2.5 i kN.
F_1_y = 5kN cos45 =3.5355 j kN ( j = + ve).
F_1_z = 5kN cos60 = 2.5 i kN.

F_1 = 2.5i +3.54j+2.5j kN.

F_2 = 0i + 2kN(-j)+ 0k = -2 j kN.

Hence option [A].
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