Engineering Mechanics - Force Vectors - Discussion
Discussion Forum : Force Vectors - General Questions (Q.No. 15)
15.
Determine the magnitude of the x and y components of the 700-lb force.
Discussion:
4 comments Page 1 of 1.
Pramod Pant said:
9 years ago
Magnitude of x = 700 cos (90 + 60) = -sin60 * 700 = -606.
Magnitude of y = 700 cos60 =350.
Magnitude of y = 700 cos60 =350.
Naven said:
9 years ago
Fx: 700cos30 (-ve value).
=> - 606lb.
Fy: 700cos60 (+ve value).
=> 350lb.
You need to sketch and figure the angle involved.
=> - 606lb.
Fy: 700cos60 (+ve value).
=> 350lb.
You need to sketch and figure the angle involved.
Esas Khan said:
10 years ago
How come? I have no idea how am I getting my answer but I don't think it's an appropriate approach. Can someone solve this?
Angel said:
1 decade ago
Answer it please!
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