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Engineering Mechanics - Force Vectors - Discussion

Discussion Forum : Force Vectors - General Questions (Q.No. 21)
Force Vectors
21.

Determine the magnitude of the x and y components of the 2—kN force.

Fx = -1.414 kN, Fy = -1.414 kN
Fx = -1.000 kN, Fy = -1.732 kN
Fx = -1.732 kN, Fy = -1.000 kN
Fx = -4.000 kN, Fy = -2.312 kN
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.
YOSEPH said:   1 decade ago
But if we use instead of it as.

Fx = -2kNcos60 and Fy = -2kNsin60 then it will be,

Fx = -1.732kN and Fy = -1.000kN.
(1)
Renuka batta said:   1 decade ago
In the x-direction the angle is 120 therefore fx=2*cos (180-60) =-1.000kN,

fy=2*sin (180+60) =-1.732kN.
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