Engineering Mechanics - Force Vectors - Discussion

Discussion :: Force Vectors - General Questions (Q.No.21)

21. 

Determine the magnitude of the x and y components of the 2—kN force.

[A]. Fx = -1.414 kN, Fy = -1.414 kN
[B]. Fx = -1.000 kN, Fy = -1.732 kN
[C]. Fx = -1.732 kN, Fy = -1.000 kN
[D]. Fx = -4.000 kN, Fy = -2.312 kN

Answer: Option B

Explanation:

No answer description available for this question.

Renuka Batta said: (Jun 19, 2012)  
In the x-direction the angle is 120 therefore fx=2*cos (180-60) =-1.000kN,

fy=2*sin (180+60) =-1.732kN.

Yoseph said: (Dec 24, 2013)  
But if we use instead of it as.

Fx = -2kNcos60 and Fy = -2kNsin60 then it will be,

Fx = -1.732kN and Fy = -1.000kN.

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