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Engineering Mechanics - Force System Resultants - Discussion

Discussion Forum : Force System Resultants - General Questions (Q.No. 9)
Force System Resultants
9.

Replace the loading by an equivalent force and couple moment acting at point O.

R = 90 kN, M = 473 kN-m CW
R = 90 kN, M = 338 kN-m CW
R = 45 kN, M = 203 kN-m CW
R = 135 kN, M = 270 kN-m CW
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.
MD SALAHUDDIN said:   8 years ago
Trapezoidal load =1/2(a+b)*h,
1/2(15+5)*9=1/2*20*9=10*9=90kN.
MD SALAHUDDIN said:   8 years ago
Trapezoidal load =1/2(a+b)*h,
1/2(15+5)*9=1/2*20*9=10*9=90kN.
Karthik said:   1 decade ago
Given is a trapezoidal varying load that load split in to two load triangle and rectangular loads rectangular load 5*9=45,

Triangle load b=9 h=15-5=10 then. 5* (9*10) = 45 total load 90 trapezoidal is addition of rectangular and triangular load.
Nikhil said:   1 decade ago
Please explan this answer.
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