Engineering Mechanics - Force System Resultants - Discussion

Discussion :: Force System Resultants - General Questions (Q.No.9)

9. 

Replace the loading by an equivalent force and couple moment acting at point O.

[A]. R = 90 kN, M = 473 kN-m CW
[B]. R = 90 kN, M = 338 kN-m CW
[C]. R = 45 kN, M = 203 kN-m CW
[D]. R = 135 kN, M = 270 kN-m CW

Answer: Option B

Explanation:

No answer description available for this question.

Nikhil said: (Feb 15, 2012)  
Please explan this answer.

Karthik said: (Apr 9, 2012)  
Given is a trapezoidal varying load that load split in to two load triangle and rectangular loads rectangular load 5*9=45,

Triangle load b=9 h=15-5=10 then. 5* (9*10) = 45 total load 90 trapezoidal is addition of rectangular and triangular load.

Md Salahuddin said: (Dec 19, 2017)  
Trapezoidal load =1/2(a+b)*h,
1/2(15+5)*9=1/2*20*9=10*9=90kN.

Md Salahuddin said: (Dec 19, 2017)  
Trapezoidal load =1/2(a+b)*h,
1/2(15+5)*9=1/2*20*9=10*9=90kN.

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