Engineering Mechanics - Force System Resultants - Discussion

Discussion :: Force System Resultants - General Questions (Q.No.4)

4. 

Replace the force at A by an equivalent force and couple moment at P.

[A]. F = 15 kN @ = 36.9° , Mp = 67.1 kN-m
[B]. F = 15 kN @ = 36.9° , Mp = 30 kN-m
[C]. F = 15 kN @ = 143.1° , Mp = 67.1 kN-m
[D]. F = 15 kN @ = 143.1° , Mp = 30 kN-m

Answer: Option A

Explanation:

No answer description available for this question.

Channy said: (Mar 10, 2017)  
how that moment is calculated?

Explain it.

Tejas said: (Aug 5, 2017)  
Why option (A)? Explain.

Babai Mukherjee said: (Jan 11, 2019)  
@All.

1st of all resolved the 15kN force. It should be 15 cos θ and 15 sin θ.
And now look at the triangle given there you can determine the value of there. It should be Sin θ =3/4 and cos θ =5/4.

Now, calculate the moment about pond p .so force is 15sin(3/4)*6 (6 is distant) = 67.5.

Birhanu Biadge said: (Apr 6, 2021)  
Anyone explain this in detail.

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