Engineering Mechanics - Force System Resultants - Discussion
Discussion Forum : Force System Resultants - General Questions (Q.No. 4)
4.
Replace the force at A by an equivalent force and couple moment at P.
F = 15 kN @ 
= 36.9° 
, Mp = 67.1 kN-m
= 36.9° , Mp = 67.1 kN-m F = 15 kN @ = 36.9° , Mp = 30 kN-m
= 36.9° , Mp = 30 kN-m F = 15 kN @ = 143.1° 
, Mp = 67.1 kN-m
= 143.1° , Mp = 67.1 kN-m F = 15 kN @ = 143.1° , Mp = 30 kN-m
= 143.1° , Mp = 30 kN-m Discussion:
4 comments Page 1 of 1.
Birhanu Biadge said:
4 years ago
Anyone explain this in detail.
Babai Mukherjee said:
7 years ago
@All.
1st of all resolved the 15kN force. It should be 15 cos θ and 15 sin θ.
And now look at the triangle given there you can determine the value of there. It should be Sin θ =3/4 and cos θ =5/4.
Now, calculate the moment about pond p .so force is 15sin(3/4)*6 (6 is distant) = 67.5.
1st of all resolved the 15kN force. It should be 15 cos θ and 15 sin θ.
And now look at the triangle given there you can determine the value of there. It should be Sin θ =3/4 and cos θ =5/4.
Now, calculate the moment about pond p .so force is 15sin(3/4)*6 (6 is distant) = 67.5.
Tejas said:
8 years ago
Why option (A)? Explain.
Channy said:
8 years ago
how that moment is calculated?
Explain it.
Explain it.
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