Engineering Mechanics - Force System Resultants - Discussion

Discussion Forum : Force System Resultants - General Questions (Q.No. 2)
2.

Determine the moment of force F1 about point A on the beam.

M1 = 1600 ft-lb
M1 = 100 ft-lb
M1 = 100 ft-lb
M1 = 1600 ft-lb
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
7 comments Page 1 of 1.

Atchuth said:   7 years ago
Moment=force * distance.

By observing the beam we have one force on the left side, apply moment formula.
F1* 4=m(A).
400 * 4==1600.

Ftanegest said:   10 years ago
It is well. But it needs more clarifications.

Md Mahfooz said:   1 decade ago
How can I derive moment?

Mayuresh Date said:   1 decade ago
According to fundamental principles, we can apply a balance force system anywhere along the rigid body.

So if we apply at point A a balance force system of 400lb vertically upward and downward, they will cancel out each other and net effect remains the same but the force F1 will form a couple with the vertical 400lb force at A.

The moment of a couple is nothing but the product of one of the force of couple and its couple arm which is here 4ft, Since the couple is a vector qty, hence we will get the answer as 400*4=1600lb-ft in counterclockwise direction.

Albert villaganas said:   1 decade ago
Do you have a deeper explanation and solution regarding on this problem?

Kusha kumar.poloju said:   1 decade ago
* {r_{OF}} is the vector from point A to the position where quantity F1 is applied.
* represents the cross product of the vectors.

Therefore,
M1=force(F1)*perpendicular distance(4ft),
M1=400lb*4ft,
M1=1600ft-lb.
And the direction is getting from right hand screw principle as anti-clockwise direction.

Karthik said:   1 decade ago
Simply we know the M=F*D then 400*horizontal distance (4) =1600 anticlockwise moment.

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