Engineering Mechanics - Force System Resultants - Discussion
Discussion Forum : Force System Resultants - General Questions (Q.No. 7)
7.
Determine the magnitude and direction of the moment of the force of the movement if the force at A about point P.
Mp = 1440 Nm 
Mp = 600 Nm 
Mp = 1440 Nm
Mp = 600 Nm
Discussion:
2 comments Page 1 of 1.
Kailas said:
1 decade ago
We know
Moment=force * perpendicular distance
But here force is inclined
Hence fist find angle and then resolve force into 2 component
ANGLE=22.62(degree)
[tan9(thita)=vertical component/horizontal component]
=5/12=22.62].
Hence
M=6*260sin(22.62)
=600(clockwise).
Moment=force * perpendicular distance
But here force is inclined
Hence fist find angle and then resolve force into 2 component
ANGLE=22.62(degree)
[tan9(thita)=vertical component/horizontal component]
=5/12=22.62].
Hence
M=6*260sin(22.62)
=600(clockwise).
Varad said:
9 years ago
We know that,
angle = tan - 1(5/12) = 22.61.
angle = 90-22.61 = 67.39.
Mp = 120cos67.39 * 6.
Mp = 599.00 (clockwise).
angle = tan - 1(5/12) = 22.61.
angle = 90-22.61 = 67.39.
Mp = 120cos67.39 * 6.
Mp = 599.00 (clockwise).
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