Engineering Mechanics - Force System Resultants - Discussion
Discussion Forum : Force System Resultants - General Questions (Q.No. 3)
3.
Determine the magnitude and direction of the moment of the force of the movement if the force at A about point P.
Mp = 400 Nm 
Mp = 400 Nm 
Mp = 200 Nm
Mp = 200 Nm
Discussion:
5 comments Page 1 of 1.
A.Kalyan kumar said:
8 years ago
m=F*D(force in the perpendicular distance).
Hence moment about point p due to force 200n is,
M=200*2=400(clockwise).
Hence moment about point p due to force 200n is,
M=200*2=400(clockwise).
Rajneeshkumar said:
1 decade ago
M=F*D (force into perpendicular distance).
Hence moment about point p due to force 200n is
M=+200*2=400(clockwise).
Hence moment about point p due to force 200n is
M=+200*2=400(clockwise).
Kailas jadhav said:
1 decade ago
M=F*D (force into perpendicular distance).
Hence moment about point p due to force 200n is
M=+200*2=400(clockwise).
Hence moment about point p due to force 200n is
M=+200*2=400(clockwise).
Kusha kumar.poloju said:
1 decade ago
Moment =force * perpendicular distance between the two forces
M=200*2
M=400 N-m
(With respect to point P direction of moment is clockwise).
M=200*2
M=400 N-m
(With respect to point P direction of moment is clockwise).
(1)
Swapnil dafal said:
1 decade ago
So simple
moment =force * perpendicular distance between the two forces
M=200*2
M=400 N-m
(with respect to point P direction of moment is clockwise).
moment =force * perpendicular distance between the two forces
M=200*2
M=400 N-m
(with respect to point P direction of moment is clockwise).
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