Engineering Mechanics - Equilibrium of a Rigid Body - Discussion

Just take moment about A;

You get (17*9.81*450) +(10*9.81*450) = 2RB*750
As RB = RC at mid, it will be 2RB.

From here you will get RB = RC = 60N,
Now take moment about 2RB.

You will get (300*10*9.81) +(475*17*9.81) = RA*750.
From here RA = 144.9 N.

Hence option C is the Correct answer.

Please answer the question that 3 cylinders are placed in a rectangular channel or shown in the figure. Determine the reaction between the cylinder 1 and vertical wall.

Force at Gg = 17g N where g=9.81
Force at Gt = 10g N

Distance Gg -> A = 450
Distance Gg -> CD = 300

Force A = 300/750 * 17g = 66.6 N
Force CD = 450/750 * 17g = 100N

Distance Gt -> A = 275
Distance Gt -> CD = 425

Force A = 425/700 * 10g = 59.5N
Force CD = 275/700 * 10g = 38.5N

Total force A = 59.5+66.4 = 126 N (which is close approx.)
Total force CD = 100+38.5 = 138.5N
Force at each wheel = 138.5/2 = 69N (approx.)

B is the closest answer

please answer