Engineering Mechanics - Equilibrium of a Particle - Discussion
Discussion Forum : Equilibrium of a Particle - General Questions (Q.No. 2)
2.
A "scale" is constructed with a 4-ft-long cord and the 10-lb block D. The cord is fixed to a pin at A and passes over two small pulleys at B and C. Determine the weight of the suspended block E if the system is in equilibrium when s = 1.5 ft.
Discussion:
15 comments Page 2 of 2.
Prasanna said:
10 years ago
I didn't understand you are explanation.
Ram said:
8 years ago
Anyone, can explain clearly?
Balaji said:
7 years ago
(angle)BCD= 23.578.
Then calculating the tension in string BC. Let it be called T.
Now T is affected totally by the 10lb block.
So,
T= 10cos= 10cos23.578=9.1651.
(Note : We're taking 10cos' because only the cos component of the force due to 10lb block is acting in string BC).
Tension in AB = Tension in BC =T.
Mass of E = T in AB +T in BC,
So, 9.1651+9.1651= 18.3302 ~ 18.33lb.
Then calculating the tension in string BC. Let it be called T.
Now T is affected totally by the 10lb block.
So,
T= 10cos= 10cos23.578=9.1651.
(Note : We're taking 10cos' because only the cos component of the force due to 10lb block is acting in string BC).
Tension in AB = Tension in BC =T.
Mass of E = T in AB +T in BC,
So, 9.1651+9.1651= 18.3302 ~ 18.33lb.
Siva said:
6 years ago
How do you find bc = 1.25?
Kaliraj said:
5 years ago
I got the θ value as 18.34°.
How all getting 23°? Please explain to me.
How all getting 23°? Please explain to me.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers