Engineering Mechanics - Center of Gravity and Centroid - Discussion
Discussion Forum : Center of Gravity and Centroid - General Questions (Q.No. 3)
3.
Locate the centroid of the shaded area.
= 0.667 m, 
= 2.40 m = 0.500 m, = 2.80 m = 0.800 m, = 2.00 m = 0.600 m, = 2.60 mDiscussion:
8 comments Page 1 of 1.
Shashi said:
7 years ago
@Anand.
Didn't understand, please explain clearly.
Didn't understand, please explain clearly.
Sravani said:
8 years ago
Can anyone explain the solution?
Bindumadhavi said:
9 years ago
Please give me the explanation of the solution.
Abhishek Anand said:
9 years ago
y = (8x)^.5 - 2x .
Now apply X(centroid) = integration of y.xdx from 0 to 2/integration of y dx from 0 to 2(Area).
You will get X =.8 m, similarly for Y.
Now apply X(centroid) = integration of y.xdx from 0 to 2/integration of y dx from 0 to 2(Area).
You will get X =.8 m, similarly for Y.
(2)
Rakesh said:
9 years ago
Please give me the explanation of the solution.
Chinni said:
9 years ago
Some of know all answers some body don't know so please give answers.
Emeka said:
1 decade ago
It's quite easy. If you still need it, inform me.
(1)
Parvathi said:
1 decade ago
Please give me solution for above problem.
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