Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 18)
18.
If 40 C of charge flow past a point in 20 s, what is the current?
Discussion:
33 comments Page 1 of 4.
Amandeep Singh said:
1 decade ago
Quantity symbols units
coloumbs=current*time, Q=I*t , C=A*s,
coloumb/time=current , Q/t=I , C/s=A
40/20=2A
coloumbs=current*time, Q=I*t , C=A*s,
coloumb/time=current , Q/t=I , C/s=A
40/20=2A
Arun said:
1 decade ago
Current = Charge flowing in 1 second.
Charge flowing in 20 second = 40C.
Charge flowing in 1 second = 40C/20s = 2A.
Charge flowing in 20 second = 40C.
Charge flowing in 1 second = 40C/20s = 2A.
Shanmu sanjay said:
9 years ago
Current is the rate of flow of charge.
So, Current = Charge/Time.
Coulombs = 40 C.
Time = 20 s.
40c/20s = 2 A.
So, Current = Charge/Time.
Coulombs = 40 C.
Time = 20 s.
40c/20s = 2 A.
Nileshpatel said:
1 decade ago
GIVEN; C = 40C T = 20s.
Answer: Coulomb = 40c, Time = 20s.
I = Coulomb/Time.
= 40/20.
= 2A.
Answer: Coulomb = 40c, Time = 20s.
I = Coulomb/Time.
= 40/20.
= 2A.
Leninbabu said:
1 decade ago
Current = Coulombs/Time.
So here given values is 40 c & 20 s.
Therefore 40c/20s = 2 A.
So here given values is 40 c & 20 s.
Therefore 40c/20s = 2 A.
Rajendra said:
1 decade ago
Current = coulombs/time.
1. Coulombs = 40 c.
2. Time = 20 s.
Therefore current = 2 amps.
1. Coulombs = 40 c.
2. Time = 20 s.
Therefore current = 2 amps.
(1)
Chinna said:
1 decade ago
Charge=current*time
q=it
i=q/t
given that q=40c
t=20sec
i=40/20 A
i=2A.
q=it
i=q/t
given that q=40c
t=20sec
i=40/20 A
i=2A.
Siyum abate said:
9 years ago
Current(I) = charge(Q)/time(T).
= 40C/20s,
= 2A.
= 40C/20s,
= 2A.
AFZAL said:
1 decade ago
We know that
Current= charge/time
I=Q/T
OR
I=C/T
C=40
T=20s
I=40/20
I=2A
Current= charge/time
I=Q/T
OR
I=C/T
C=40
T=20s
I=40/20
I=2A
Shivakumar said:
1 decade ago
Current = coloumb/time i.e I=C/t.
Given: c=40c t=20s I=?
I=40/20=2A.
Given: c=40c t=20s I=?
I=40/20=2A.
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