Electronics - Voltage and Current - Discussion

One of my friend written 1/2*c*v*v formula and he got 8j as the answer,

Here c is capacitance, but in question c is charge so we have to apply voltage= (energy/charge).

E=1/2*c*v^2 from this V=8v then which formula apply for this question?

W = QV, SO V = W/Q, THEN V = 60/15, V = 4VOLT

Voltage is the electric potential energy per unit charge.

V = E/Q
V = 60/14
V = 4 volt

P=W/t
Therefore W=P*t
And P=V*I
So W=V*I*t
Now q=I*t
Therefore W=V*q
So V=W/q=60/15=4V

Voltage = Energy/Charge.

V = 60/15.

V = 4.

I=Q/T &........1
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.

P=I^2 R.

I=V/R from ohm law,

Then P=V^2R.

R=V/I.

We get V=P/I.

V=60j/15c.

=4V.

Chetan Kumar and Jaimin Patel Gujarat you both are wrong why because
you said that Energy=1/2CV^2
It's Correct for Electrical Energy stored in a Capacitor Only.
Then
U=QV/2=CV^2/2

Where U=Potential Energy
Q=Coulombs(C)
V=Volts(V)
C=Capacitance in frads.

But In the above problem we should use the formula that
Energy(Q)=Charge(C)*Voltage(V)
Q=CV
V=Q/C; Where V stands for Voltage

Thanks to all of you and especially for Vinod who told that Chetan was wrong.If we know the correct answer then only we can say that to anyone But to say it's wrong we should have guts that type of daring i got from Vinod.Thank you Vinod.

Energy = Charge*Voltage.

In the above question we need to know Voltage So.

Voltage = Energy/Charge.

Energy (Q) = 60Joules.

Charge (C) = 15C.

Therefore Voltage = 60J/15C = 4V.

Thank you friends.