Electronics - Voltage and Current - Discussion

V = E/C V:VOLTAGE, C:COLOUMN and E:ENERGY.

= 60/15 .

= 4 .

V = Energy/Charge.

V = 60/15.

V = 4.

Energy = Charge*Voltage.

In the above question we need to know Voltage So.

Voltage = Energy/Charge.

Energy (Q) = 60Joules.

Charge (C) = 15C.

Therefore Voltage = 60J/15C = 4V.

Thank you friends.

Chetan Kumar and Jaimin Patel Gujarat you both are wrong why because
you said that Energy=1/2CV^2
It's Correct for Electrical Energy stored in a Capacitor Only.
Then
U=QV/2=CV^2/2

Where U=Potential Energy
Q=Coulombs(C)
V=Volts(V)
C=Capacitance in frads.

But In the above problem we should use the formula that
Energy(Q)=Charge(C)*Voltage(V)
Q=CV
V=Q/C; Where V stands for Voltage

Thanks to all of you and especially for Vinod who told that Chetan was wrong.If we know the correct answer then only we can say that to anyone But to say it's wrong we should have guts that type of daring i got from Vinod.Thank you Vinod.

P=I^2 R.

I=V/R from ohm law,

Then P=V^2R.

R=V/I.

We get V=P/I.

V=60j/15c.

=4V.

I=Q/T &........1
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.

Voltage = Energy/Charge.

V = 60/15.

V = 4.

P=W/t
Therefore W=P*t
And P=V*I
So W=V*I*t
Now q=I*t
Therefore W=V*q
So V=W/q=60/15=4V

Voltage is the electric potential energy per unit charge.

V = E/Q
V = 60/14
V = 4 volt

W = QV, SO V = W/Q, THEN V = 60/15, V = 4VOLT