Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 5 of 17.
Preeth said:
1 decade ago
I feel vinay is right.
Ruchi Mishra said:
1 decade ago
I=Q/T &........1
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.
Brijesh rathod said:
1 decade ago
E=QV
V=E/Q
V=60/15
V=4
Where:-
E=energy measured in joules.
Q=charge measured in coulomb.
v=voltage measured in volt.
V=E/Q
V=60/15
V=4
Where:-
E=energy measured in joules.
Q=charge measured in coulomb.
v=voltage measured in volt.
Arun Jain said:
1 decade ago
E = 1/2 * C * V^2
With the help of this Einsten Eq. the Ans. Should be 8V.
but this is not a option, so we can go through to this way
I= Q/T &........1
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.
With the help of this Einsten Eq. the Ans. Should be 8V.
but this is not a option, so we can go through to this way
I= Q/T &........1
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.
Mahesh said:
1 decade ago
Voltage is defined as the energy per unit charge.
Sarath kumar said:
1 decade ago
v = voltage;
e = energy in joules = 60
Q = charge in couloumbs = 15
v = e/q => 60/15
*v = 4;
e = energy in joules = 60
Q = charge in couloumbs = 15
v = e/q => 60/15
*v = 4;
Bhargav said:
1 decade ago
Joules are volt-coulombs; that is, when you put one coulomb of electrons through a potential difference of 1 volt, you do one joule of work on the system. So you find the number of joules of work (or energy put in to the system) by multiplying the number of coulombs by the number of volts.
Anju said:
1 decade ago
The potential difference or voltage, V across two points is defined as energy, E dissipated or transferred by coulomb of charge, Q that moves through the two points.
Therefore:
Potential difference = Electrical energy dissipated
Charge
V= E /Q
V= Voltage
E= Energy
Q= Charge
Therefore:
Potential difference = Electrical energy dissipated
Charge
V= E /Q
V= Voltage
E= Energy
Q= Charge
BOOPATHI said:
1 decade ago
E=energy measured in joules.
Q=charge measured in coulomb.
v=voltage measured in volt.
V=60/15
V=4 volt
Q=charge measured in coulomb.
v=voltage measured in volt.
V=60/15
V=4 volt
Abhinai said:
1 decade ago
V=SQRT OF(2*E/C)
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