Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 2 of 17.
Jeevan Thakare said:
9 years ago
Power = volt * current.
Current is the amount of charge flowing through a cross section of the conductor in unit time here 't'.
So, current =15/t and the power is energy dissipates in time t so here 60/t.
60/t = volt*15/t.
volt = 4 volt.
Current is the amount of charge flowing through a cross section of the conductor in unit time here 't'.
So, current =15/t and the power is energy dissipates in time t so here 60/t.
60/t = volt*15/t.
volt = 4 volt.
Avinash.A said:
1 decade ago
The definition of potential or voltage is workdone in moving a charge from one point to another. So 1V is defined as 1J of energy spent in moving 1C of charge so here 60J of energy is demanding in moving 15C of charge so potential is 4V.
Prerna agrawal said:
1 decade ago
An ideal capacitor is wholly characterized by a constant capacitance C, defined as the ratio of charge Q on each conductor to the voltage V between them
c = q/v.
So rearrange above equation,
v = q/c.
v = 60/15.
v = 4v.
c = q/v.
So rearrange above equation,
v = q/c.
v = 60/15.
v = 4v.
Saru said:
1 decade ago
The potential energy is a form of energy and the potential (and therefore voltage, when differences are taken) is defined as the potential energy (or potential energy difference) per unit charge, V=E/Q.
V = 60/15 = 4.
V = 60/15 = 4.
Narendran A I said:
6 years ago
Joule is energy gained by 1 coulomb of charge when placed in a potential difference of 1 volt.
Hence, Joule = Coulomb times Volt.
Given, Energy =60 J, Charge = 15 C therefore Voltage =(60/15) = 4 Volts.
Hence, Joule = Coulomb times Volt.
Given, Energy =60 J, Charge = 15 C therefore Voltage =(60/15) = 4 Volts.
(9)
Hitesh virani said:
1 decade ago
60/15 = 4 Volts.
It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps
60/t = V * 15/t.
V = 4.
It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps
60/t = V * 15/t.
V = 4.
Ramyasri.Ch said:
1 decade ago
Energy = Charge*Voltage.
In the above question we need to know Voltage So.
Voltage = Energy/Charge.
Energy (Q) = 60Joules.
Charge (C) = 15C.
Therefore Voltage = 60J/15C = 4V.
Thank you friends.
In the above question we need to know Voltage So.
Voltage = Energy/Charge.
Energy (Q) = 60Joules.
Charge (C) = 15C.
Therefore Voltage = 60J/15C = 4V.
Thank you friends.
Deepak arya said:
1 decade ago
It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts.
Watts = Volts * Amps.
60/t = V * 15/t.
V = 4.
Watts = Volts * Amps.
60/t = V * 15/t.
V = 4.
Sandeep said:
9 years ago
It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts.
Watts = Volts * Amps.
60/t = V * 15/t.
V = 4.
Watts = Volts * Amps.
60/t = V * 15/t.
V = 4.
Sahana949 said:
1 decade ago
It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps
60/t = V * 15/t
V = 4
60/t = V * 15/t
V = 4
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