Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 2 of 17.
T. Lakshmi said:
2 decades ago
w=60J q=15C
v= w/q
v=60/15
v=4v
v= w/q
v=60/15
v=4v
Srinaga said:
2 decades ago
Hey
Here problem is about a single charge . if suppose +Ve charge has 15C charge and has energy 60 J than what is the value of potential generated by it.
we can not treat it as capacitor because in capacitor we treat the potential difference applied between plates.so kindly have it simple case. E = q . V = = 4 volt
Here problem is about a single charge . if suppose +Ve charge has 15C charge and has energy 60 J than what is the value of potential generated by it.
we can not treat it as capacitor because in capacitor we treat the potential difference applied between plates.so kindly have it simple case. E = q . V = = 4 volt
Shakeer said:
2 decades ago
Thanks to all.
Kinjal patel said:
2 decades ago
energy = charge 8 columb
= 60 j/15 c
= 4 v
= 60 j/15 c
= 4 v
Swapnil said:
2 decades ago
Let V=voltage to be found, I=current passing through the circuit in time 't' & Q=charge in coulombs. Then, electrical power P & current I are given by
P=V*I.....(1)
&
I=dQ/dt...(2)
so, the electrical energy E is
E=V*Q.....(3)
Since E=60 J(Given) & Q=15 C(Given),
V=E/Q=(60/15) V =4 V
P=V*I.....(1)
&
I=dQ/dt...(2)
so, the electrical energy E is
E=V*Q.....(3)
Since E=60 J(Given) & Q=15 C(Given),
V=E/Q=(60/15) V =4 V
Bharatesh said:
2 decades ago
E=Q*V
V=Q/V
=60/15
=4v
V=Q/V
=60/15
=4v
YOGESHWARI MAHANTI said:
2 decades ago
Charge= Energy/voltage
Q = E/V
60 = 15/V
V = 4V
Q = E/V
60 = 15/V
V = 4V
Universal said:
1 decade ago
1 Joule = 1coulomb * 1voltage
Coolfunnyguy said:
1 decade ago
E=(1/2)*C*[(V)^2]
v^2=(2*E)/C ==>v^2=2*60/15
v^2=8
V=~4V
v^2=(2*E)/C ==>v^2=2*60/15
v^2=8
V=~4V
Sahana949 said:
1 decade ago
It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps
60/t = V * 15/t
V = 4
60/t = V * 15/t
V = 4
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