Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 12 of 17.
Pradeep said:
1 decade ago
I think your relation give the above problem right.
Mahesh said:
1 decade ago
Voltage is defined as the energy per unit charge.
Mahesh Yadav said:
9 years ago
E=Q * V.
60J = 15Q * V,
V = 60J ÷15Q,
V = 4V.
60J = 15Q * V,
V = 60J ÷15Q,
V = 4V.
YOGESHWARI MAHANTI said:
1 decade ago
Charge= Energy/voltage
Q = E/V
60 = 15/V
V = 4V
Q = E/V
60 = 15/V
V = 4V
Kinjal patel said:
1 decade ago
energy = charge 8 columb
= 60 j/15 c
= 4 v
= 60 j/15 c
= 4 v
Peeyush said:
1 decade ago
W = QV, SO V = W/Q, THEN V = 60/15, V = 4VOLT
CHINNAPPAR.E said:
1 decade ago
Voltage = Power/Charge.
So, v = 60/15 = 4 v.
So, v = 60/15 = 4 v.
Sonali k said:
9 years ago
Watts = Volts * Amps,
60/t = V * 15/t,
V = 4.
60/t = V * 15/t,
V = 4.
Ramesh nirjogi said:
1 decade ago
v=w/q
v=60/15
v=4v
or
p=vi
p=v(q/t)
e=pt=vq
v=60/15
v=4v
or
p=vi
p=v(q/t)
e=pt=vq
Ramraj said:
1 decade ago
Voltage= no of joules / coulomb.
60/15=4v.
60/15=4v.
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