Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 12 of 17.
KOMAL SHARMA said:
1 decade ago
V = ENERGY/CHARGE.
V = 16/15.
V = 4.
V = 16/15.
V = 4.
Yogesh mahajan said:
1 decade ago
To find voltage.
Given Energy = 60j.
Charge = 15.
By formula V = E/C = 60/15 = 4.
Given Energy = 60j.
Charge = 15.
By formula V = E/C = 60/15 = 4.
Joshi Girish V. said:
1 decade ago
The Unit For The Measurement Of Charge Is Coulomb Which is Equal To 6.28*10^18 Electrons/Second.
The Unit For The Measurement Of Current Is Ampere Which Is Equal To 1 Coulomb/Second.
Therefore, Current = 15C/Second.
Electrical Energy = Power*Time = 60J (KWH).
Power = Current*Voltage.
Therefore, Electrical Energy = Current*Voltage*Time.
Therefore, 60J = 15C*Voltage*1 Second.
Therefore, Voltage = 60J/15C*1.
Therefore, Voltage = 4V*1.
Therefore, Voltage = 4V.
The Unit For The Measurement Of Current Is Ampere Which Is Equal To 1 Coulomb/Second.
Therefore, Current = 15C/Second.
Electrical Energy = Power*Time = 60J (KWH).
Power = Current*Voltage.
Therefore, Electrical Energy = Current*Voltage*Time.
Therefore, 60J = 15C*Voltage*1 Second.
Therefore, Voltage = 60J/15C*1.
Therefore, Voltage = 4V*1.
Therefore, Voltage = 4V.
CHINNAPPAR.E said:
1 decade ago
Voltage = Power/Charge.
So, v = 60/15 = 4 v.
So, v = 60/15 = 4 v.
Muji said:
1 decade ago
Voltage = (Work done/Charge).
Energy is ability to do work.
So, Voltage = (w/q).
= (E/q).
= 60/15.
= 4 volt.
Energy is ability to do work.
So, Voltage = (w/q).
= (E/q).
= 60/15.
= 4 volt.
Mohan said:
1 decade ago
Energy = 1/2(CV^2).
C = Charge.
V = Voltage.
V^2 = 2E/C.
V^2 = (40/3).
V = 3.6.
V = 4.
C = Charge.
V = Voltage.
V^2 = 2E/C.
V^2 = (40/3).
V = 3.6.
V = 4.
Dattatreya said:
1 decade ago
E = q*v.
60 = 15.v.
v = 60/15 = 4V.
60 = 15.v.
v = 60/15 = 4V.
Aman said:
1 decade ago
Energy = qV.
Since electric field strength is E = F/q = V/d.
With V = voltage, d = distance between charged plates.
Fd = qV.
Energy = qv.
Since electric field strength is E = F/q = V/d.
With V = voltage, d = distance between charged plates.
Fd = qV.
Energy = qv.
Sonu Kumar said:
1 decade ago
Energy = C*V.
60 = 15*V.
V = 60/15.
V = 4.
60 = 15*V.
V = 60/15.
V = 4.
Pradeep said:
1 decade ago
I think your relation give the above problem right.
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