Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 11 of 17.
Deepak arya said:
1 decade ago
It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts.
Watts = Volts * Amps.
60/t = V * 15/t.
V = 4.
Watts = Volts * Amps.
60/t = V * 15/t.
V = 4.
Aditya said:
1 decade ago
E = eV.
e = 15 C.
E = 60.
There 4V = E/e = 60/15 = 4.
e = 15 C.
E = 60.
There 4V = E/e = 60/15 = 4.
Sachidananda swain said:
1 decade ago
Let V=voltage to be found, I=current passing through the circuit in time 't' & Q=charge in coulombs. Then, electrical power P & current I are given by,
P = V*I.....(1).
&
I = dQ/dt...(2).
So, the electrical energy E is:
E = V*Q.....(3).
Since E = 60 J(Given) & Q = 15 C(Given),
V = E/Q = (60/15). V = 4 V.
P = V*I.....(1).
&
I = dQ/dt...(2).
So, the electrical energy E is:
E = V*Q.....(3).
Since E = 60 J(Given) & Q = 15 C(Given),
V = E/Q = (60/15). V = 4 V.
VamsiKrishna said:
1 decade ago
Energy stored by the capacitor in the form of charge.
Given by Energy (Q) = Charge (c) X Voltage (v).
60= 15 X Voltage.
Voltage = 60/15 = 4v.
Given by Energy (Q) = Charge (c) X Voltage (v).
60= 15 X Voltage.
Voltage = 60/15 = 4v.
Pradeep kushwaha said:
1 decade ago
p=power=60
c=current=15
findout=v
we know that p=v*i so
v=p/i
v=60/15=4v
c=current=15
findout=v
we know that p=v*i so
v=p/i
v=60/15=4v
Lakshmi byreddy said:
1 decade ago
E=qV.
Where E=60J and q=15c.
Then V=4V.
Where E=60J and q=15c.
Then V=4V.
Sibly sadik said:
1 decade ago
We know that, energy = voltage*charge.
So charge = energy/voltage.
Let, V = 60/15 = 4v.
Answer: 4v.
So charge = energy/voltage.
Let, V = 60/15 = 4v.
Answer: 4v.
KUMUDINI said:
1 decade ago
We know Q = CV.
V = Q/C.
V= 60/15 = 4V.
V = Q/C.
V= 60/15 = 4V.
Prerna agrawal said:
1 decade ago
An ideal capacitor is wholly characterized by a constant capacitance C, defined as the ratio of charge Q on each conductor to the voltage V between them
c = q/v.
So rearrange above equation,
v = q/c.
v = 60/15.
v = 4v.
c = q/v.
So rearrange above equation,
v = q/c.
v = 60/15.
v = 4v.
Vijay soni said:
1 decade ago
The problem is for only one charge, hence capacitor fundamental can't be applied, therefore simple energy relation can be used here i.e.
E = q*v.
=> v = E/q.
v = 60/15.
v = 4V.
E = q*v.
=> v = E/q.
v = 60/15.
v = 4V.
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