Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 10 of 17.
Shahid said:
1 decade ago
Voltage is equal to work per unit charge.
V = w/q.
V = 60/15 = 4.
V = w/q.
V = 60/15 = 4.
M.Naresh said:
1 decade ago
E = 1/2*C*(V)^2
where E = Energy, C = Capicitanence, V = Voltage
where E = Energy, C = Capicitanence, V = Voltage
Vinayagamoorthi said:
1 decade ago
Voltage = Energy/degree
=60/15
=4
=60/15
=4
Suren said:
1 decade ago
I agree that energy is the multiplication of voltage and charge.
Vijay said:
1 decade ago
i be the charge(15c)/time and p be the power 60j/watt so
p= vi
p= vi
Sushil said:
8 years ago
Q=60J
C=15C
V=?
we have,
Q=c*v
or,60=15*v
or,v=60/15
So,v=4V.
C=15C
V=?
we have,
Q=c*v
or,60=15*v
or,v=60/15
So,v=4V.
SADANANDAM said:
1 decade ago
V=W/Q; GENERAL FORMULA;
I.E
V=?
W=P=E=60;
Q=15;
60/15=4;//ANS
I.E
V=?
W=P=E=60;
Q=15;
60/15=4;//ANS
Amit singh said:
1 decade ago
V=W/Q; GENERAL FORMULA;
I.E
V=?
W=P=E=60;
Q=15;
60/15=4;//ANS
I.E
V=?
W=P=E=60;
Q=15;
60/15=4;//ANS
Coolfunnyguy said:
1 decade ago
E=(1/2)*C*[(V)^2]
v^2=(2*E)/C ==>v^2=2*60/15
v^2=8
V=~4V
v^2=(2*E)/C ==>v^2=2*60/15
v^2=8
V=~4V
DHANRAJ said:
1 decade ago
V = E/C V:VOLTAGE, C:COLOUMN and E:ENERGY.
= 60/15 .
= 4 .
= 60/15 .
= 4 .
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