# Electronics - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 10)

10.

What is the power dissipated in the primary of the transformer in the given circuit?

Discussion:

9 comments Page 1 of 1.
Sohail khan said:
5 years ago

Power will be 62.5 watt, not mw and current will also in ampere not in mili because resistance is in kilo ohm not just 1 ohm.

Akshay said:
7 years ago

How, v2 = 250 please explain.

PrivUsr said:
8 years ago

A simple explanation - primary power equal to secondary power in a transformer. Assuming this holds, then.

V2 = 50 * 5 = 250 V.

P2 = V**2 / R = 62.5 W.

For a transformer, the AC voltage & current could be different but power remain equal.

V2 = 50 * 5 = 250 V.

P2 = V**2 / R = 62.5 W.

For a transformer, the AC voltage & current could be different but power remain equal.

Ankur said:
10 years ago

v2/v1=n2/n1. So v2=250v,

According to ohm's law v = ir.

i2 = v2/r2 = 250mA.

i1/i2 = v2/v1. So i1=1250 mA.

p=vi So pin=v1*i1=50*1250 = 62.5W.

According to ohm's law v = ir.

i2 = v2/r2 = 250mA.

i1/i2 = v2/v1. So i1=1250 mA.

p=vi So pin=v1*i1=50*1250 = 62.5W.

Tito said:
1 decade ago

Input power and Output power should be the same, therefore calculate secondary power by v^2/r.

250^2/1000 = 62.5w.

250^2/1000 = 62.5w.

Chayan said:
1 decade ago

We have,

Ip/Is = Ns/Np =>Ip = (Ns/Np)*Is ------(i).

Is = Vs/Rl--------(ii).

where Vs = (Ns/Np)*Vp.

Which gives Is = 250mA.

Thus we ve from eqn (i).

Ip = 1.25A.

Therefore, Pp = V*Ip = 62.5W.

Ip/Is = Ns/Np =>Ip = (Ns/Np)*Is ------(i).

Is = Vs/Rl--------(ii).

where Vs = (Ns/Np)*Vp.

Which gives Is = 250mA.

Thus we ve from eqn (i).

Ip = 1.25A.

Therefore, Pp = V*Ip = 62.5W.

Sivalaxmi said:
1 decade ago

Please check this way is correct or not sir/mam r= 1kohm 1*1000, v=250.

p=v^/r

=250*250/1000

=62.5 w

answer is 62.5.

p=v^/r

=250*250/1000

=62.5 w

answer is 62.5.

RAJU said:
1 decade ago

It is very simple

r1/r2=sqr(n1/n2) so r1=?

r2=1k

r1=r2*sqr(n1/n2)

r1=40ohm

p=v^2/r

p=62.5W

r1/r2=sqr(n1/n2) so r1=?

r2=1k

r1=r2*sqr(n1/n2)

r1=40ohm

p=v^2/r

p=62.5W

Varsha said:
1 decade ago

It is very simple

v2/v1=n2/n1 so v2=250v

according to ohm's law v=ir

i2=v2/r2=250mA

i1/i2=v2/v1 so i1=1250 mA

p=vi so pin=v1*i1=50*1250=62.5mW

v2/v1=n2/n1 so v2=250v

according to ohm's law v=ir

i2=v2/r2=250mA

i1/i2=v2/v1 so i1=1250 mA

p=vi so pin=v1*i1=50*1250=62.5mW

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