Electronics - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 10)
10.
What is the power dissipated in the primary of the transformer in the given circuit?
Discussion:
9 comments Page 1 of 1.
Sohail khan said:
6 years ago
Power will be 62.5 watt, not mw and current will also in ampere not in mili because resistance is in kilo ohm not just 1 ohm.
Akshay said:
8 years ago
How, v2 = 250 please explain.
PrivUsr said:
9 years ago
A simple explanation - primary power equal to secondary power in a transformer. Assuming this holds, then.
V2 = 50 * 5 = 250 V.
P2 = V**2 / R = 62.5 W.
For a transformer, the AC voltage & current could be different but power remain equal.
V2 = 50 * 5 = 250 V.
P2 = V**2 / R = 62.5 W.
For a transformer, the AC voltage & current could be different but power remain equal.
Ankur said:
1 decade ago
v2/v1=n2/n1. So v2=250v,
According to ohm's law v = ir.
i2 = v2/r2 = 250mA.
i1/i2 = v2/v1. So i1=1250 mA.
p=vi So pin=v1*i1=50*1250 = 62.5W.
According to ohm's law v = ir.
i2 = v2/r2 = 250mA.
i1/i2 = v2/v1. So i1=1250 mA.
p=vi So pin=v1*i1=50*1250 = 62.5W.
(1)
Tito said:
1 decade ago
Input power and Output power should be the same, therefore calculate secondary power by v^2/r.
250^2/1000 = 62.5w.
250^2/1000 = 62.5w.
Chayan said:
1 decade ago
We have,
Ip/Is = Ns/Np =>Ip = (Ns/Np)*Is ------(i).
Is = Vs/Rl--------(ii).
where Vs = (Ns/Np)*Vp.
Which gives Is = 250mA.
Thus we ve from eqn (i).
Ip = 1.25A.
Therefore, Pp = V*Ip = 62.5W.
Ip/Is = Ns/Np =>Ip = (Ns/Np)*Is ------(i).
Is = Vs/Rl--------(ii).
where Vs = (Ns/Np)*Vp.
Which gives Is = 250mA.
Thus we ve from eqn (i).
Ip = 1.25A.
Therefore, Pp = V*Ip = 62.5W.
Sivalaxmi said:
1 decade ago
Please check this way is correct or not sir/mam r= 1kohm 1*1000, v=250.
p=v^/r
=250*250/1000
=62.5 w
answer is 62.5.
p=v^/r
=250*250/1000
=62.5 w
answer is 62.5.
RAJU said:
1 decade ago
It is very simple
r1/r2=sqr(n1/n2) so r1=?
r2=1k
r1=r2*sqr(n1/n2)
r1=40ohm
p=v^2/r
p=62.5W
r1/r2=sqr(n1/n2) so r1=?
r2=1k
r1=r2*sqr(n1/n2)
r1=40ohm
p=v^2/r
p=62.5W
Varsha said:
1 decade ago
It is very simple
v2/v1=n2/n1 so v2=250v
according to ohm's law v=ir
i2=v2/r2=250mA
i1/i2=v2/v1 so i1=1250 mA
p=vi so pin=v1*i1=50*1250=62.5mW
v2/v1=n2/n1 so v2=250v
according to ohm's law v=ir
i2=v2/r2=250mA
i1/i2=v2/v1 so i1=1250 mA
p=vi so pin=v1*i1=50*1250=62.5mW
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