Electronics - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 9)
9.
What is the current through the load in the given circuit?
Discussion:
6 comments Page 1 of 1.
Sohail khan said:
6 years ago
If the secondary voltage is 250 v then current will be according to ohms law V = IR that is 250/1000 = 0.29 A.
Minakshi Talkokul said:
7 years ago
I=V/R.
=50/1000,
= 0.005,
And ratio is 1:5.
Therefore 0.005*5=0.25=250mA.
=50/1000,
= 0.005,
And ratio is 1:5.
Therefore 0.005*5=0.25=250mA.
(1)
Srinivas said:
9 years ago
According to ohms law. V=IR.
I = V/R.
I =250/.
= 250.
So the given answer is correct.
I = V/R.
I =250/.
= 250.
So the given answer is correct.
Asha said:
1 decade ago
Given v1=50v, r2=1kohm,
N1:N2 = 1:5.
v2/v1 = N2/N1.
So v2 = 50*5/1 = 250V.
I2= v2/r2 = 250/1000 = 250mA.
N1:N2 = 1:5.
v2/v1 = N2/N1.
So v2 = 50*5/1 = 250V.
I2= v2/r2 = 250/1000 = 250mA.
Niv said:
1 decade ago
Vs=Ns/Np.Vp
Vs=5/1*50
Vs=250
Vs=IR
250/1=I
I=250
Vs=5/1*50
Vs=250
Vs=IR
250/1=I
I=250
Yogeshwaran said:
1 decade ago
Its very simple.
According to ohms law. V=IR.
So I=V/R. I=250/1 = 250.
According to ohms law. V=IR.
So I=V/R. I=250/1 = 250.
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