Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 2)
2.
What is the power dissipated by R2, R4, and R6?
Discussion:
45 comments Page 2 of 5.
Jorge said:
1 decade ago
Hello if is possible I would like to see the answer procedure step by step of this exercise. Thank you.
2. What is the power dissipated by R2, R4, and R6?
2. What is the power dissipated by R2, R4, and R6?
Jorda said:
10 years ago
Pr2 = Vr2(I1-I2).
I1 = 0.01778 A.
I2 = 0.01058 A.
I3 = 0.00529 A.
= 57.9 V (0.01778 A-0.01058 A).
= 0.417 W.
Pr4 = Vr4 (I2-I3).
Pr6 = Vr6 (I3).
I1 = 0.01778 A.
I2 = 0.01058 A.
I3 = 0.00529 A.
= 57.9 V (0.01778 A-0.01058 A).
= 0.417 W.
Pr4 = Vr4 (I2-I3).
Pr6 = Vr6 (I3).
Kim said:
10 years ago
Guys can somebody explain this step by step like finding required, voltage drops, currents of each resistors and also the power of each things.
Mahesh Reddy said:
1 decade ago
We can use this also I think. Please correct me if I am wrong.
P=V2/R. We know that voltage will be same across all the branches i.e. 111.
P=V2/R. We know that voltage will be same across all the branches i.e. 111.
HAPPY said:
9 years ago
Leave all concepts, I want to know how the current is find in this question? We want to know the starting 3 steps. (i1, i2, i3)?
Priya said:
1 decade ago
In this we use mesh analysis method for current flowing. where have to find
I1=delta1/delta;
I2=delta2/delta;
I3=delta3/delta
I1=delta1/delta;
I2=delta2/delta;
I3=delta3/delta
Vinay said:
1 decade ago
Can anybody please tell me what is total current in the circuit and the voltage drop at R2 step by step.
Christine said:
7 years ago
I can't understand, can someone please elaborate further and use terminologies we all understand kindly?
(1)
Nagesh said:
9 years ago
By using superposition theorem.
We will find out current at resistors, so by using i*i*r we find power.
We will find out current at resistors, so by using i*i*r we find power.
(1)
Hanis said:
7 years ago
When you do the loop?
how do you get Equation 1: 11kI1-8kI2-111 = 0, where does the 11KI1 come from?
how do you get Equation 1: 11kI1-8kI2-111 = 0, where does the 11KI1 come from?
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