Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 19)
19.
What is the voltage to the load?


Discussion:
3 comments Page 1 of 1.
Carlo said:
6 years ago
R2//RL=3.155K.
RT= R2//RL+R1 = 7.155k.
It=35/RT =4.89mA.
VL= Itotal * R2//RL = 15.4V.
RT= R2//RL+R1 = 7.155k.
It=35/RT =4.89mA.
VL= Itotal * R2//RL = 15.4V.
Mudassar said:
1 decade ago
Rt = R2!!RL+R1 = 7.155.
IL = Vin/Rt.
I = (IL*R2)/R1+R2.
Voltage Drop across RL,
VL = I/RL.
IL = Vin/Rt.
I = (IL*R2)/R1+R2.
Voltage Drop across RL,
VL = I/RL.
Nishant said:
1 decade ago
R2 is parallel to RL & inseries with R1=7.155
total current is 35/7.155=4.895
current division rule in between r2& RL4
4.895*7.8/7.8+5.3=2.9
now voltage drop in RL is
2.9*5.3=15.4v
total current is 35/7.155=4.895
current division rule in between r2& RL4
4.895*7.8/7.8+5.3=2.9
now voltage drop in RL is
2.9*5.3=15.4v
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