Discussion :: Series-Parallel Circuits - Filling the Blanks (Q.No.3)
In the given circuit, the current flowing through R3 equals ______.
Answer: Option A
No answer description available for this question.
|Deepak Jr said: (Oct 4, 2016)|
|How this? Explain me.|
|Sapana M A said: (Sep 16, 2017)|
|By applying KVL for both loops we get following equations.
-100I1+ 1000I2= -19,
so we get I1=90mA.
So across R3 current I2 is flowing which is 10mA.
|Sapana Adhalli said: (Sep 20, 2017)|
|200 I1 - 100 I2= 19 --> equation 1.
-100 I1 + 1000 I2 = -19 --> equation 2.
solving equation 1 and 2 we get,
I1 =90mA and I2 which is accross R3 that is I2 = -10mA.
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