Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 15)
15.
How much voltage is dropped across R3 in the given circuit?
Discussion:
10 comments Page 1 of 1.
Harshitha said:
1 decade ago
Parallel resistance along R2,R3,R4=24
Total resistance= R1+(R2||R3||R4) =92
Total current= (v/i)= 46/92 =0.5A
Voltage drop across R3= 24*0.5= 12v
Total resistance= R1+(R2||R3||R4) =92
Total current= (v/i)= 46/92 =0.5A
Voltage drop across R3= 24*0.5= 12v
Salini said:
10 years ago
I am not getting 24 in parallel resistor value.
Pinkie said:
10 years ago
Meaning of ||?
Prathmesh said:
10 years ago
|| means parallel.
Balasabarish said:
10 years ago
Parallel resistance along R2, R3, R4 = 24.
Total resistance = R1+ (R2||R3||R4) = 92.
Total current = (v/i) = 46/92 = 0.5 A.
Voltage drop across R1 = Total current*R1 = 34.
Voltage drop across R3 = Source Voltage - Voltage drop across R1.
= 46-34 = 12 V.
Total resistance = R1+ (R2||R3||R4) = 92.
Total current = (v/i) = 46/92 = 0.5 A.
Voltage drop across R1 = Total current*R1 = 34.
Voltage drop across R3 = Source Voltage - Voltage drop across R1.
= 46-34 = 12 V.
Hamsanandhini said:
9 years ago
It is very easy. Thanks for the explanation.
Raja said:
9 years ago
@Balasabarish.
Why did you use R1*.5. Should you use R3*.5 rite?
Why did you use R1*.5. Should you use R3*.5 rite?
Rohit said:
7 years ago
In question, it asked voltage drop at R3 terminal and 24 is the parallel resistance of the circuit.
Kumar said:
6 years ago
Parallel resistance along R2, R3, R4 = 24.
Total resistance= R1+(R2||R3||R4) = 92,
Total current= (v/i)= 46/92 =0.5A,
Voltage drop across R3= 24 * 0.5 = 12.
Total resistance= R1+(R2||R3||R4) = 92,
Total current= (v/i)= 46/92 =0.5A,
Voltage drop across R3= 24 * 0.5 = 12.
(1)
Varun said:
5 years ago
What is parallel resistance along R2, R3, R4?
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