Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 13)
13.
If the load in the given circuit is open, what is the unloaded output voltage?
Discussion:
2 comments Page 1 of 1.
Manoj bhat said:
1 decade ago
Find the current in the circuit:
Add R1 & R2 which are in series.
R1+R2 = 10 kohm.
Current, I = 2 m amps.
Since vout is taken,
V = IR1.
V = 2m*2k.
V = 4V.
Therefore Vout = 20-4 = 16V.
Add R1 & R2 which are in series.
R1+R2 = 10 kohm.
Current, I = 2 m amps.
Since vout is taken,
V = IR1.
V = 2m*2k.
V = 4V.
Therefore Vout = 20-4 = 16V.
Divya said:
1 decade ago
Unloaded o/p volt. means rl=0
Therefore r1&r2 are in series
i=v/r=20/(2k+8k)=2mA
v across r2 is
v=ir=2m*8k=16.
Therefore r1&r2 are in series
i=v/r=20/(2k+8k)=2mA
v across r2 is
v=ir=2m*8k=16.
(1)
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