Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 3)
3.
If the load in the given circuit is 120 k
, what is the loaded output voltage?
Discussion:
19 comments Page 1 of 2.
AKHIL VA said:
6 years ago
resistor 120k is parallel with 8k.
So r=1/120+1/8 = 7.5k.
vout=r2/(r1+r2) = 7.5/((2+7.5).
= 15.78947368421053 V,
= 15.79 V.
So r=1/120+1/8 = 7.5k.
vout=r2/(r1+r2) = 7.5/((2+7.5).
= 15.78947368421053 V,
= 15.79 V.
(5)
Aravind said:
8 years ago
8k parallel 10k= (8*120)/(8+120)= 7.5k.
Now,
Voltage across 7.5k = Vol.across 120k (bz 8k parallel 120k)
So vol across 7.5k =(20V * 7.5k)/2k + 7.5k,
= 15.79V.
(Vol.divider equation)
Now,
Voltage across 7.5k = Vol.across 120k (bz 8k parallel 120k)
So vol across 7.5k =(20V * 7.5k)/2k + 7.5k,
= 15.79V.
(Vol.divider equation)
(5)
Alex said:
7 years ago
Is this series, parallel, or an open circuit? Please tell me.
(2)
Vc_davv said:
8 years ago
Don't be so complex.
Use thevenin theorem.
So vth = 16 v and Rth = 1.6 kohm.
Voltage across Rl (load 120kohm) by VDL = (16*120K/120k+1.6k)=15.7v.
Use thevenin theorem.
So vth = 16 v and Rth = 1.6 kohm.
Voltage across Rl (load 120kohm) by VDL = (16*120K/120k+1.6k)=15.7v.
(1)
Karthik said:
1 decade ago
In the Given Circuit RL=120K
So RL and R2 in parallel,
R2=8K
1/R=1/R2+1/RL
1/R=1/8+1/120
1/R=0.13333
R=7.5K
THEN R AND R1 IN SERIES SO TOTAL R =9.5K
CURRENT I =0.0021A
SO
VL = I*R VL=0.0021*7.5K
VL =15.75..
Thanks,
Karthik
So RL and R2 in parallel,
R2=8K
1/R=1/R2+1/RL
1/R=1/8+1/120
1/R=0.13333
R=7.5K
THEN R AND R1 IN SERIES SO TOTAL R =9.5K
CURRENT I =0.0021A
SO
VL = I*R VL=0.0021*7.5K
VL =15.75..
Thanks,
Karthik
(1)
Manoj said:
9 years ago
Thanks @Rekha.
Thiru said:
8 years ago
Can we choose this method?
Apply *voltage Divider Rule *
V=((Total voltage *opposite Resistance) /Total Resistance)
20*8/8+2=16V.
Whatever the Voltage across parallel is same as the other side That's why its 16v.
Apply *voltage Divider Rule *
V=((Total voltage *opposite Resistance) /Total Resistance)
20*8/8+2=16V.
Whatever the Voltage across parallel is same as the other side That's why its 16v.
Shik shansha vali said:
8 years ago
RL = 120 anyone can explain?
Pragadee said:
8 years ago
Thanks for explaining this.
Vaishnavi said:
8 years ago
Thanks for explaining it.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers