Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - Filling the Blanks (Q.No. 5)
5.
If four 10 k
resistors are in series with a single 20 k
resistor and one of the parallel resistors shorts, the voltage across the other parallel resistors ________.


Discussion:
8 comments Page 1 of 1.
ANIL KUMAR said:
9 years ago
If one Resistor is short in parallel connection means here Resistance in parallel circuit is zero. It means voltage drop in parallel circuit is zero.
Santosh said:
9 years ago
From this question, if one of the resistor in parallel connection shorted means over all resistance of parallel is zero show from the ohm's law V = I*R.
If R decreases voltage also decresed.
If R decreases voltage also decresed.
Tim J said:
1 decade ago
Here again, I almost forgot: As related to my last response.
I*R = V. So let's just use a random current value for the proof of say 6mA.
= (1/10*4) = 2.5K (1/10*3) = 3.33K.
= 6mA*2.5Kohm = 15 volts.
6mA*3.3Kohm = 19.8 volts, so I believe the answer may be that current decreases when one of the resistors burns out.
If the same voltage were applied to the circuit then current would definitely decrease. You can look at the question either way but the result is the same.
V = I*R.
I*R = V. So let's just use a random current value for the proof of say 6mA.
= (1/10*4) = 2.5K (1/10*3) = 3.33K.
= 6mA*2.5Kohm = 15 volts.
6mA*3.3Kohm = 19.8 volts, so I believe the answer may be that current decreases when one of the resistors burns out.
If the same voltage were applied to the circuit then current would definitely decrease. You can look at the question either way but the result is the same.
V = I*R.
Tim J said:
1 decade ago
Here is the answer. If one of the 4 resistors in parallel shorts, the resistance in the entire circuit increases. Whether or not 20K ohm is present or not it would still increase. Here is the proof:
1/10+1/10+1/10+1/10 or 1/10*4 = 400*10-3 (x-1) is reciprocal = 2.5 ohms.
1/10+1/10+1/10 or 1/10*3 = 300 E-3 reciprocal = 3.33 ohms!
1/10+1/10+1/10+1/10 or 1/10*4 = 400*10-3 (x-1) is reciprocal = 2.5 ohms.
1/10+1/10+1/10 or 1/10*3 = 300 E-3 reciprocal = 3.33 ohms!
Afash said:
1 decade ago
Voltage is same in parallel connection. So how it is possible that voltage be decreased. Here some twist in the Q.
Rm bahuguna said:
1 decade ago
Because all the four 10 k ohm resisters are in parallel so voltage across other three resister will drop to zero, if get shorted.
Neelaji said:
1 decade ago
As per the circuit analysis most of the current is passed through the short circuit.In question how much voltage drop across parallel resistors.
ANSWER IS INCREASES because according to ohms law v is proportional to I
ANSWER IS INCREASES because according to ohms law v is proportional to I
Sanjeet singh said:
1 decade ago
The question is not clear. Which parallel connection is it talking about. Please explain me.
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