Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - True or False (Q.No. 5)
5.
The voltmeter will read 18 volts.
Discussion:
3 comments Page 1 of 1.
Ranjan said:
1 decade ago
Can you please explain me about the about the answer.
Shreya said:
1 decade ago
Lets say point between R8 and R10 be A and point between R7 and R9 be B.
Now, R8, R10 in series so Rt1 = 2+3 = 5 ohm.
And R7, R9 in series so Rt2 = 1+4 = 5 ohm.
Rt=(Rt1Rt2)/(Rt1+Rt2) = 5/2 ohm.
Total current = V/Rt = (90*2)/5 = 36 amp.
Since Rt1 and Rt2 are equal therefore equal current will flow through each branch = 36/2 = 18 amp.
Voltage drop across R8 = 18*2 = 36v.
Potential at point A = 90-36 = 54v.
Voltage drop across R7 = 18*1 = 18v.
Potential at point B = 90-18 = 72v.
Potential diff. between A and B gives voltmeter reading = 72-54 = 18v.
Now, R8, R10 in series so Rt1 = 2+3 = 5 ohm.
And R7, R9 in series so Rt2 = 1+4 = 5 ohm.
Rt=(Rt1Rt2)/(Rt1+Rt2) = 5/2 ohm.
Total current = V/Rt = (90*2)/5 = 36 amp.
Since Rt1 and Rt2 are equal therefore equal current will flow through each branch = 36/2 = 18 amp.
Voltage drop across R8 = 18*2 = 36v.
Potential at point A = 90-36 = 54v.
Voltage drop across R7 = 18*1 = 18v.
Potential at point B = 90-18 = 72v.
Potential diff. between A and B gives voltmeter reading = 72-54 = 18v.
(2)
KIRAN V said:
9 years ago
Good explanation @Shreya.
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