Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - True or False (Q.No. 13)
13.
The current through R6 is 8.5 mA.
Discussion:
4 comments Page 1 of 1.
Manjunath said:
1 decade ago
Can anyone solve this?
Mohammed Z.K said:
9 years ago
I think the correct answer is 4.85 mA.
KIRAN V said:
9 years ago
I6 = V / R6.
I6 = 85 / 1 * 10^3
I6 = 0.085 = 85 mA.
I6 = 85 / 1 * 10^3
I6 = 0.085 = 85 mA.
Dan Philip said:
6 years ago
Here, the correct answer is 4.72mA.
By getting the voltage drop across R2 you will get the remaining voltage which is equal to the resistance to the right =9.44v.
By getting the current (9.44/R5+R6) R5 is also involve since they have the same current
By getting the voltage drop across R2 you will get the remaining voltage which is equal to the resistance to the right =9.44v.
By getting the current (9.44/R5+R6) R5 is also involve since they have the same current
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