Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 9)
9.
What is the total resistance of a circuit when R1 (7 k 
) is in series with a parallel combination of R2 (20 k ), R3 (36 k ), and R4 (45 k )?
) is in series with a parallel combination of R2 (20 k ), R3 (36 k ), and R4 (45 k )?4 k
17 k
41 k
108 k
Discussion:
5 comments Page 1 of 1.
Prasanna said:
1 decade ago
RT = R1 + ( 1/R2 + 1/R3 + 1/R4)
= 7+(1/20 + 1/36 + 1/45)
=7+(10)
=17 Kohms
= 7+(1/20 + 1/36 + 1/45)
=7+(10)
=17 Kohms
(1)
Nandini said:
1 decade ago
Can you explain the answer?
Nandakishor said:
1 decade ago
Since parallel combination of resisitor is lees than least resistance . therefore parallel combination of 20 36 45 is less than 20. for this combination a series resistance of 7 is added .max answer is less than 20+7=27 there c and d options are not correct . a is also not correct because 7+anything is greater than 7.
There fore the correct answer is 17 which is option B.
There fore the correct answer is 17 which is option B.
Revathi said:
1 decade ago
The equivalent resistance for resistors connected in parallel is 1/Re = ((1/R2)+(1/R3)+(1/R4)).
B Nagendar said:
1 decade ago
In parallel resistors 1/R = (1/R2+1/R3+1/R4).
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