Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 38)
38.
If series resistors dissipate 16 mW, 107 mW, 146 mW, and 243 mW, what is the total power consumed by the circuit?
Discussion:
3 comments Page 1 of 1.
Aziz Murtza said:
9 years ago
P1+ P2+ P3+ P4 = 16 + 107 + 146 + 243 = 512 mW.
Prasanna said:
1 decade ago
Total Power in series or parallel
P1+ p2+ p3+ p4+.....
P1+ p2+ p3+ p4+.....
Asha said:
1 decade ago
Usually power consumed can be determined by knowing the disspation across the resistors.
So total disspation = 16m+107m+146m+243m=512mw.
So total disspation = 16m+107m+146m+243m=512mw.
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