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Electronics - Series Circuits - Discussion

Discussion Forum : Series Circuits - General Questions (Q.No. 6)
Series Circuits
6.
With a total resistance of 3300 ohms and a 45 V source, if R3 is 1200 ohms, what will be its voltage drop?
16.36 V
32.72 V
10.90 V
15.00 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 2 of 2.
Jaime romero said:   1 decade ago
Total resistance= 3300 ohms
Total voltage=45V
R3= 1200 ohms
V3= total voltage*R3/total resistance
V3=45*1200ohms/3300ohms
V3=16.36V
A is the correct answer
Ramesh.H.Adavalli said:   1 decade ago
V/R=R/V
45/3300=R/1200
=16.36V
Shaibal Santua said:   1 decade ago
Total resistance= 3300 ohms
Total voltage=45V
R3= 1200 ohms
V3= total voltage*R3/total resistance
V3=45*1200ohms/3300ohms
V3=16.36V
so option A is correct.
Chenthamil selvn said:   1 decade ago
Total resistance = 3300 omhs.
Total voltage = 45 V
So,Total current = Total voltage/Total resistance.
Total current= 45/3300 => 0.0136 A
R3 = 1200 omhs
Voltage drop across it = I*R3
V3 = .0136*1200
V3 = 16.36 V (A answer)
Vikas Dhaniya said:   1 decade ago
Total resistance = 3300 omhs.
Total voltage = 45 V
So,Total current = Total voltage/Total resistance.
Total current= 45/3300 => 0.0136 A
R3 = 1200 omhs
Voltage drop across it = I*R3
V3 = .0136*1200
V3 = 16.36 V (A answer)
M.PANDIYARAJAN said:   1 decade ago
Itotal=Vtotal/Rtotal

Itotal=45/3300

Itotal=0.0136

VR3=IR3*R3

VR3=0.0136*1200

VR3=16.32
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