Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 6)
6.
With a total resistance of 3300 ohms and a 45 V source, if R3 is 1200 ohms, what will be its voltage drop?
Discussion:
16 comments Page 1 of 2.
M.PANDIYARAJAN said:
1 decade ago
Itotal=Vtotal/Rtotal
Itotal=45/3300
Itotal=0.0136
VR3=IR3*R3
VR3=0.0136*1200
VR3=16.32
Itotal=45/3300
Itotal=0.0136
VR3=IR3*R3
VR3=0.0136*1200
VR3=16.32
Vikas Dhaniya said:
1 decade ago
Total resistance = 3300 omhs.
Total voltage = 45 V
So,Total current = Total voltage/Total resistance.
Total current= 45/3300 => 0.0136 A
R3 = 1200 omhs
Voltage drop across it = I*R3
V3 = .0136*1200
V3 = 16.36 V (A answer)
Total voltage = 45 V
So,Total current = Total voltage/Total resistance.
Total current= 45/3300 => 0.0136 A
R3 = 1200 omhs
Voltage drop across it = I*R3
V3 = .0136*1200
V3 = 16.36 V (A answer)
Chenthamil selvn said:
1 decade ago
Total resistance = 3300 omhs.
Total voltage = 45 V
So,Total current = Total voltage/Total resistance.
Total current= 45/3300 => 0.0136 A
R3 = 1200 omhs
Voltage drop across it = I*R3
V3 = .0136*1200
V3 = 16.36 V (A answer)
Total voltage = 45 V
So,Total current = Total voltage/Total resistance.
Total current= 45/3300 => 0.0136 A
R3 = 1200 omhs
Voltage drop across it = I*R3
V3 = .0136*1200
V3 = 16.36 V (A answer)
Shaibal Santua said:
1 decade ago
Total resistance= 3300 ohms
Total voltage=45V
R3= 1200 ohms
V3= total voltage*R3/total resistance
V3=45*1200ohms/3300ohms
V3=16.36V
so option A is correct.
Total voltage=45V
R3= 1200 ohms
V3= total voltage*R3/total resistance
V3=45*1200ohms/3300ohms
V3=16.36V
so option A is correct.
Ramesh.H.Adavalli said:
1 decade ago
V/R=R/V
45/3300=R/1200
=16.36V
45/3300=R/1200
=16.36V
Jaime romero said:
1 decade ago
Total resistance= 3300 ohms
Total voltage=45V
R3= 1200 ohms
V3= total voltage*R3/total resistance
V3=45*1200ohms/3300ohms
V3=16.36V
A is the correct answer
Total voltage=45V
R3= 1200 ohms
V3= total voltage*R3/total resistance
V3=45*1200ohms/3300ohms
V3=16.36V
A is the correct answer
Suresh said:
1 decade ago
I = V/R.
= 45/3300 = 9/660,
GIVEN R3 = 1200 Then V3 = ?,
In series combination current is same,
V = 1200*(9/660) = 16.36v.
= 45/3300 = 9/660,
GIVEN R3 = 1200 Then V3 = ?,
In series combination current is same,
V = 1200*(9/660) = 16.36v.
GAURAV KUMAR said:
1 decade ago
V = 45V.
R = 3300 OHMS.
I = V/R.
I = 45/3300 = 0.013636363 A.
R3 = 1200 OHMS.
V3 = R3*I.
= 1200*0.01363636 = 16.36 VOLTS.
R = 3300 OHMS.
I = V/R.
I = 45/3300 = 0.013636363 A.
R3 = 1200 OHMS.
V3 = R3*I.
= 1200*0.01363636 = 16.36 VOLTS.
(2)
Sai said:
1 decade ago
We know that.
Voltage drop across resistor is (V*R3) /total R.
Such that (45*1200) /3300.
Answer = 16.3636.
Voltage drop across resistor is (V*R3) /total R.
Such that (45*1200) /3300.
Answer = 16.3636.
Bipul said:
1 decade ago
There is no block diagram of the circuit. Then how do we know that which one is R1, R2 or R3?
(1)
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