Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 17)
17.
If three resistors of 1.5 kilohms, 470 ohms, and 3300 ohms are in series with a 25-volt source, what is the total circuit current?
Discussion:
7 comments Page 1 of 1.
Munsif Ali said:
4 years ago
I = Voltage/Total resistance,
I = 25/1500 + 470 + 3300,
I = 4.7 mA.
I = 25/1500 + 470 + 3300,
I = 4.7 mA.
(1)
Hafees said:
10 years ago
@Mahalaxmi : The total resistance of resistors in series is equal to the sum of their individual resistances.
Mahalaxmi r s said:
1 decade ago
Sir its wrong answers. If resistors are connected in series means then we have to add as 1/R1+1/R2 not as R1+R2.
Manoj khanadre1 said:
1 decade ago
= 25v/1500+470+3300R = 4.7 MA.
Santhi said:
1 decade ago
V=25
R1=1500 ohm
R2=470 0hm
R3=3300 0hm
I=V/R
I=25/5270=0.0047a=4.7ma
R1=1500 ohm
R2=470 0hm
R3=3300 0hm
I=V/R
I=25/5270=0.0047a=4.7ma
(1)
Naseem Ul Aziz said:
1 decade ago
R1=1500 ohm
R2=470 ohm
R3=3300 ohm
Rt=5270 Ohm
it=25(vt)/5270(rt)=0.0047 a
that is 4.7 m ampere
R2=470 ohm
R3=3300 ohm
Rt=5270 Ohm
it=25(vt)/5270(rt)=0.0047 a
that is 4.7 m ampere
R.Anjana Velmurugan said:
1 decade ago
Here V=25V
Total resistance=1500+470+3300=5270 ohms
Total Current = V/I
= 25/5270 = 4.7 mA
Total resistance=1500+470+3300=5270 ohms
Total Current = V/I
= 25/5270 = 4.7 mA
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