Electronics - Series Circuits - Discussion

3. 

If the resistance total in a series circuit doubles, current will:

[A]. be the same
[B]. be doubled
[C]. reduce source voltage
[D]. be halved

Answer: Option D

Explanation:

No answer description available for this question.

Rakesh Mohapatra said: (Apr 24, 2011)  
As v=ir,so v=1/2(i)*(2r)
so current is halved

Anuja Shelke said: (May 24, 2011)  
i=v/r & if the resistance is doubled then the current will be
i=v/2r. which is half of the previous.

Arun Jain said: (Aug 25, 2011)  
By Ohm's Law Voltage(V) is directly praprotional to Current(C), and by Ohm's R is a praprotionality Constant, So In a series circuit voltage is constant(we can say V = 1),than By eq.
V = IR
1 = IR (V=1)
I = 1/R
If R = 2 Then I = ?
I = 1/2
that is Halfed

Kotesh said: (Dec 25, 2011)  
In series total resistance value is 3+3+3=9 ohm's. supose in that circuit voltage is 9v.
given data R=9 ohm's
V=9v,
simlarly R=2R (given conditions),
so 2*9=18 ohms
V=IR
I=V/R
I=9/18
1/2
that is Halfed

Ahammed Najeeb said: (Jan 6, 2012)  
For example we can take a circuit given below.



In this series total resistance value is 3+3+3=9 ohm's. supose in that circuit voltage is 9v.

Given data R=9 ohm's
V=9v,

Simlarly R=2R (given conditions),
so 2*9=18 ohms
V=IR
I=V/R
I=9/18
1/2

That is halved.

Sreeyush Sudhakaran said: (Feb 18, 2012)  
Case 1:
V=IxR
case 2:
V=I'x2R

Since Voltage source in both circuit is same

IxR=I'x2R

so I'=I/2

Current is halfed in second case

Nagaraj Reddy said: (Oct 25, 2013)  
We know Ohm's law V=IR.
If R is doubled then.
V = I(2R).

then,
I= V/2R.

I=(1/2)(V/R).

Hence Current Halved.

Rooshan Ashfaq said: (Jan 28, 2014)  
V=IR.
I=V/R or R=V/I.

As we see current is inversely proportional to resistance so value of current remain half if value of resistance I double.

Bhabani Shankar Behera said: (Dec 3, 2015)  
R = 2.
V = 1.
I = V/R.

So I = 1/2.

Hari said: (Mar 31, 2018)  
Explain it in detail.

Janvence said: (Jun 9, 2018)  
Thank you all for explaining it.

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