### Discussion :: Series Circuits - General Questions (Q.No.3)

Rakesh Mohapatra said: (Apr 24, 2011) | |

As v=ir,so v=1/2(i)*(2r) so current is halved |

Anuja Shelke said: (May 24, 2011) | |

i=v/r & if the resistance is doubled then the current will be i=v/2r. which is half of the previous. |

Arun Jain said: (Aug 25, 2011) | |

By Ohm's Law Voltage(V) is directly praprotional to Current(C), and by Ohm's R is a praprotionality Constant, So In a series circuit voltage is constant(we can say V = 1),than By eq. V = IR 1 = IR (V=1) I = 1/R If R = 2 Then I = ? I = 1/2 that is Halfed |

Kotesh said: (Dec 25, 2011) | |

In series total resistance value is 3+3+3=9 ohm's. supose in that circuit voltage is 9v. given data R=9 ohm's V=9v, simlarly R=2R (given conditions), so 2*9=18 ohms V=IR I=V/R I=9/18 1/2 that is Halfed |

Ahammed Najeeb said: (Jan 6, 2012) | |

For example we can take a circuit given below. In this series total resistance value is 3+3+3=9 ohm's. supose in that circuit voltage is 9v. Given data R=9 ohm's V=9v, Simlarly R=2R (given conditions), so 2*9=18 ohms V=IR I=V/R I=9/18 1/2 That is halved. |

Sreeyush Sudhakaran said: (Feb 18, 2012) | |

Case 1: V=IxR case 2: V=I'x2R Since Voltage source in both circuit is same IxR=I'x2R so I'=I/2 Current is halfed in second case |

Nagaraj Reddy said: (Oct 25, 2013) | |

We know Ohm's law V=IR. If R is doubled then. V = I(2R). then, I= V/2R. I=(1/2)(V/R). Hence Current Halved. |

Rooshan Ashfaq said: (Jan 28, 2014) | |

V=IR. I=V/R or R=V/I. As we see current is inversely proportional to resistance so value of current remain half if value of resistance I double. |

Bhabani Shankar Behera said: (Dec 3, 2015) | |

R = 2. V = 1. I = V/R. So I = 1/2. |

Hari said: (Mar 31, 2018) | |

Explain it in detail. |

Janvence said: (Jun 9, 2018) | |

Thank you all for explaining it. |

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