Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 3)
3.
If the resistance total in a series circuit doubles, current will:
Discussion:
12 comments Page 1 of 2.
Syed Shakeeb said:
4 years ago
Halved means;
Divide into two parts of equal or roughly equal size.
Divide into two parts of equal or roughly equal size.
(2)
Janvence said:
7 years ago
Thank you all for explaining it.
(1)
Hari said:
7 years ago
Explain it in detail.
BHABANI SHANKAR BEHERA said:
10 years ago
R = 2.
V = 1.
I = V/R.
So I = 1/2.
V = 1.
I = V/R.
So I = 1/2.
(1)
Rooshan Ashfaq said:
1 decade ago
V=IR.
I=V/R or R=V/I.
As we see current is inversely proportional to resistance so value of current remain half if value of resistance I double.
I=V/R or R=V/I.
As we see current is inversely proportional to resistance so value of current remain half if value of resistance I double.
(1)
Nagaraj Reddy said:
1 decade ago
We know Ohm's law V=IR.
If R is doubled then.
V = I(2R).
then,
I= V/2R.
I=(1/2)(V/R).
Hence Current Halved.
If R is doubled then.
V = I(2R).
then,
I= V/2R.
I=(1/2)(V/R).
Hence Current Halved.
Sreeyush Sudhakaran said:
1 decade ago
Case 1:
V=IxR
case 2:
V=I'x2R
Since Voltage source in both circuit is same
IxR=I'x2R
so I'=I/2
Current is halfed in second case
V=IxR
case 2:
V=I'x2R
Since Voltage source in both circuit is same
IxR=I'x2R
so I'=I/2
Current is halfed in second case
Ahammed Najeeb said:
1 decade ago
For example we can take a circuit given below.
In this series total resistance value is 3+3+3=9 ohm's. supose in that circuit voltage is 9v.
Given data R=9 ohm's
V=9v,
Simlarly R=2R (given conditions),
so 2*9=18 ohms
V=IR
I=V/R
I=9/18
1/2
That is halved.
In this series total resistance value is 3+3+3=9 ohm's. supose in that circuit voltage is 9v.
Given data R=9 ohm's
V=9v,
Simlarly R=2R (given conditions),
so 2*9=18 ohms
V=IR
I=V/R
I=9/18
1/2
That is halved.
(1)
Kotesh said:
1 decade ago
In series total resistance value is 3+3+3=9 ohm's. supose in that circuit voltage is 9v.
given data R=9 ohm's
V=9v,
simlarly R=2R (given conditions),
so 2*9=18 ohms
V=IR
I=V/R
I=9/18
1/2
that is Halfed
given data R=9 ohm's
V=9v,
simlarly R=2R (given conditions),
so 2*9=18 ohms
V=IR
I=V/R
I=9/18
1/2
that is Halfed
Arun Jain said:
1 decade ago
By Ohm's Law Voltage(V) is directly praprotional to Current(C), and by Ohm's R is a praprotionality Constant, So In a series circuit voltage is constant(we can say V = 1),than By eq.
V = IR
1 = IR (V=1)
I = 1/R
If R = 2 Then I = ?
I = 1/2
that is Halfed
V = IR
1 = IR (V=1)
I = 1/R
If R = 2 Then I = ?
I = 1/2
that is Halfed
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