Discussion :: Series Circuits  General Questions (Q.No.5)
5.  What is the dc source voltage? 

Answer: Option A Explanation: No answer description available for this question.

Sundar said: (Oct 21, 2010)  
Ohm's Law: V = IR Given I = 0.013A; R = R1+R2+R3 = (1+2+3) Kohm = 6 Kohm = 6000 ohm. Therefore, V = 0.013 * 6000 = 78 volts. 
Mintu said: (Jul 9, 2012)  
V = IR. Total R = 1+2+3 = 6Kohm. V = .013*6Kohm = 78V. 
Nivetha said: (Nov 4, 2013)  
Given that, I = 13mA. R1 = 1K, R2 = 2K, R3 = 3K. Then V = IR. V = 13*(1+2+3). V = 13*6 = 78 Volts. NOTE: Here milli amps & Kilo ohms gets cancelled. 
Saptarshi Dutta said: (Dec 9, 2013)  
V = IxRt. Rt = R1+R2+R3 = 6000 ohm. Hence, V = 0.013X6000 = 78 Volts. 
Manvendra Singh said: (Aug 26, 2015)  
V = IR. R = R1+R2+R3 = 1+2+3 = 6 kohm V = 13*6 = 78 volts. 
Sri said: (Jul 4, 2016)  
What is the resistance of 0.013A source box? 
Hatu said: (Jul 4, 2016)  
As per my understanding, 0.013A source resistance is not known. Hence answer cannot be predicted. 
Neeraj said: (Nov 19, 2016)  
@Hatu @Sri. Since it is an ammeter, And Assuming it as an ideal Ammeter with net resistance 0. 
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