Electronics - Series Circuits - Discussion

5. 

What is the dc source voltage?

[A]. 78 V
[B]. 39 V
[C]. 13 V
[D]. 0 V

Answer: Option A

Explanation:

No answer description available for this question.

Sundar said: (Oct 21, 2010)  
Ohm's Law: V = IR

Given

I = 0.013A;
R = R1+R2+R3 = (1+2+3) Kohm = 6 Kohm = 6000 ohm.

Therefore, V = 0.013 * 6000

= 78 volts.

Mintu said: (Jul 9, 2012)  
V = IR.

Total R = 1+2+3 = 6Kohm.

V = .013*6Kohm = 78V.

Nivetha said: (Nov 4, 2013)  
Given that, I = 13mA.

R1 = 1K, R2 = 2K, R3 = 3K.

Then V = IR.

V = 13*(1+2+3).
V = 13*6 = 78 Volts.

NOTE: Here milli amps & Kilo ohms gets cancelled.

Saptarshi Dutta said: (Dec 9, 2013)  
V = IxRt.

Rt = R1+R2+R3 = 6000 ohm.

Hence, V = 0.013X6000 = 78 Volts.

Manvendra Singh said: (Aug 26, 2015)  
V = IR.

R = R1+R2+R3 = 1+2+3 = 6 kohm

V = 13*6 = 78 volts.

Sri said: (Jul 4, 2016)  
What is the resistance of 0.013A source box?

Hatu said: (Jul 4, 2016)  
As per my understanding, 0.013A source resistance is not known. Hence answer cannot be predicted.

Neeraj said: (Nov 19, 2016)  
@Hatu @Sri.

Since it is an ammeter, And Assuming it as an ideal Ammeter with net resistance 0.

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