Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 5)
5.
What is the dc source voltage?
Discussion:
10 comments Page 1 of 1.
Kazi Israfil Zunaid said:
3 years ago
We know,
V = IR.
Where,
V= 0.013.
R = R1 + R2 + R3 = 1 + 2 + 3 = 6 kohm.
Whereas,
1 kohm = 1000 ohm.
so, 6 khom = 1000 * 6 = 6000 Ohm.
Then,
V=IR.
V= 0.013*6000.
78 V.
V = IR.
Where,
V= 0.013.
R = R1 + R2 + R3 = 1 + 2 + 3 = 6 kohm.
Whereas,
1 kohm = 1000 ohm.
so, 6 khom = 1000 * 6 = 6000 Ohm.
Then,
V=IR.
V= 0.013*6000.
78 V.
(9)
Khushmeet said:
3 years ago
V =IR.
I =.013 A,
V1 = IR1,
V2= IR2.
V3=IR3.
V= IR1+IR2+IR3.
V= I(R1+R2+R3).
V= .013(1+2+3)Kohm,
V= .013 * 6Kohm,
1Kohm=1000ohm.
6Kohm =6 * 1000 ohm = 6000 ohm,
V=13/1000 * 6000 = 13 * 6 = 78 V.
I =.013 A,
V1 = IR1,
V2= IR2.
V3=IR3.
V= IR1+IR2+IR3.
V= I(R1+R2+R3).
V= .013(1+2+3)Kohm,
V= .013 * 6Kohm,
1Kohm=1000ohm.
6Kohm =6 * 1000 ohm = 6000 ohm,
V=13/1000 * 6000 = 13 * 6 = 78 V.
(3)
Neeraj said:
9 years ago
@Hatu @Sri.
Since it is an ammeter, And Assuming it as an ideal Ammeter with net resistance 0.
Since it is an ammeter, And Assuming it as an ideal Ammeter with net resistance 0.
Hatu said:
9 years ago
As per my understanding, 0.013A source resistance is not known. Hence answer cannot be predicted.
Sri said:
9 years ago
What is the resistance of 0.013A source box?
MANVENDRA SINGH said:
10 years ago
V = IR.
R = R1+R2+R3 = 1+2+3 = 6 kohm
V = 13*6 = 78 volts.
R = R1+R2+R3 = 1+2+3 = 6 kohm
V = 13*6 = 78 volts.
(1)
SAPTARSHI DUTTA said:
1 decade ago
V = IxRt.
Rt = R1+R2+R3 = 6000 ohm.
Hence, V = 0.013X6000 = 78 Volts.
Rt = R1+R2+R3 = 6000 ohm.
Hence, V = 0.013X6000 = 78 Volts.
Nivetha said:
1 decade ago
Given that, I = 13mA.
R1 = 1K, R2 = 2K, R3 = 3K.
Then V = IR.
V = 13*(1+2+3).
V = 13*6 = 78 Volts.
NOTE: Here milli amps & Kilo ohms gets cancelled.
R1 = 1K, R2 = 2K, R3 = 3K.
Then V = IR.
V = 13*(1+2+3).
V = 13*6 = 78 Volts.
NOTE: Here milli amps & Kilo ohms gets cancelled.
(1)
Mintu said:
1 decade ago
V = IR.
Total R = 1+2+3 = 6Kohm.
V = .013*6Kohm = 78V.
Total R = 1+2+3 = 6Kohm.
V = .013*6Kohm = 78V.
Sundar said:
1 decade ago
Ohm's Law: V = IR
Given
I = 0.013A;
R = R1+R2+R3 = (1+2+3) Kohm = 6 Kohm = 6000 ohm.
Therefore, V = 0.013 * 6000
= 78 volts.
Given
I = 0.013A;
R = R1+R2+R3 = (1+2+3) Kohm = 6 Kohm = 6000 ohm.
Therefore, V = 0.013 * 6000
= 78 volts.
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