Electronics - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 1)
1.
What is the current flow through R1, R2, and R3?
Answer: Option
Explanation:
V = IR
V = I(R1 + R2 + R3)
I = V/(R1 + R2 + R3)
= 9/(3 + 3 + 3)
= 9/9
= 1 Amp.
Discussion:
10 comments Page 1 of 1.
Luca said:
1 decade ago
Yes, in fact, series resistors vary only the voltage, but not the current, whilst, if the resistors were placed in parallel among each other, the current will change and the voltage will remain unchanged.
Dakpo Saviour Dela Doyen said:
1 decade ago
The effective resistance in the circuit is 9 ohms and the emf is 9volts. By Ohm's law, I=V/R =9/9=1 A. Since components are in series with the voltage source the same current of 1A flow through them.
Lizzy mametja said:
1 decade ago
The answer is A because Rs. 9 and the voltage is 9 so we use I = V/R and then you will get your answer.
Veerababu said:
1 decade ago
I = V/R.
If V = 9V; R = R1+R2+R3.
= 3+3+3.
= 9.
V = 9; R = 9.
I = V/R.
I = 9/9.
I = 1 Amp.
If V = 9V; R = R1+R2+R3.
= 3+3+3.
= 9.
V = 9; R = 9.
I = V/R.
I = 9/9.
I = 1 Amp.
Saifuddin said:
9 years ago
The total resistance of the circuit is 9 ohm, so by ohm law I= Vs/Rt.
9v/9ohm = 1amp.
9v/9ohm = 1amp.
Manteshkumar said:
1 decade ago
Yes its correct because resistors are in series thats why same current will flow.
Raju said:
8 years ago
I = V/R.
V = 9V; R = 3+3+3.
= 9.
V = 9; R = 9.
I = V/R.
I = 9/9.
I = 1 Amp.
V = 9V; R = 3+3+3.
= 9.
V = 9; R = 9.
I = V/R.
I = 9/9.
I = 1 Amp.
(2)
NR Meena said:
2 years ago
The current is 1 amp, In all series resistors which are 3+3+3=9.
So, 9/9=1 amp
So, 9/9=1 amp
(1)
Krishna said:
1 decade ago
Current will be same across 3 resistor as they connected in series.
Surya said:
1 decade ago
Same current flows in series ckt.
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